[英]Pandas DataFrame equality - index numbering
Does Index numbering matter in testing dataframe equality? 索引编号在测试数据帧是否相等时重要吗? I have 2 identical dataframes with exactly the same data and columns. 我有2个完全相同的数据框和完全相同的数据和列。 The only difference is that the index numbers for each row is different and equals methods returns a False. 唯一的区别是每一行的索引号不同,并且equals方法返回False。 How can I get around this? 我该如何解决? Here are my data frames 这是我的数据框
A B
0 87 54
1 87 75
2 87 22
3 87 69
A B
418 87 69
107 87 54
108 87 75
250 87 22
You can use np.array_equal
to check the values, however the ordering is important, so in your example you have to sort by the index first. 您可以使用np.array_equal
来检查值,但是顺序很重要,因此在您的示例中,您必须首先按索引排序。
In [11]: df1
Out[11]:
A B
0 87 54
1 87 75
2 87 22
3 87 69
In [12]: df2
Out[12]:
A B
418 87 69
107 87 54
108 87 75
250 87 22
In [13]: df3 = df2.sort()
In [14]: df3
Out[14]:
A B
107 87 54
108 87 75
250 87 22
418 87 69
In [15]: np.array_equal(df1, df3)
Out[15]: True
Note: You can't compare df1 and df2 as they have different indexes: 注意:您无法比较df1和df2,因为它们具有不同的索引:
In [21]: df1 == df2
ValueError: Can only compare identically-labeled DataFrame object
You can reset the index, but be aware that an exception can be raised for that reason: 您可以重置索引,但是请注意,由于这个原因会引发异常:
In [22]: df3.reset_index(drop=True)
Out[22]:
A B
0 87 54
1 87 75
2 87 22
3 87 69
In [23]: np.all(df1 == df3.reset_index(drop=True))
Out[23]: True
Another option is to have a try and except block around assert_frame_equals
: 另一个选择是尝试一下,但在assert_frame_equals
周围进行assert_frame_equals
:
In [24]: pd.util.testing.assert_frame_equal(df1, df3.reset_index(drop=True))
as in this related answer . 就像这个相关的答案 。
As Jeff points out you can use .equals, which does this: 正如Jeff指出的那样,您可以使用.equals,它可以这样做:
In [25]: df1.equals(df3.reset_index(drop=True))
Out[25]: True
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