[英]SQL state [null]; error code [17004]; Invalid column type; nested exception is java.sql.SQLException: Invalid column type
i have a problem with my query i don't know how to deal with oracle but when i try the same code for SQL it's working but it's showing me the above error while compiling i think the problem is in the query , please someone help if knew how to deal with this.我的查询有问题我不知道如何处理 oracle 但是当我为 SQL 尝试相同的代码时它正在工作但它在编译时向我显示上述错误我认为问题出在查询中,如果有人帮忙知道如何处理这个问题。 thanks谢谢
// First class // 第一类
package com.caveofprogramming.spring.test;
import java.sql.ResultSet;
import java.sql.SQLException;
import java.util.List;
import javax.sql.DataSource;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.jdbc.core.JdbcTemplate;
import org.springframework.jdbc.core.RowMapper;
import org.springframework.jdbc.core.namedparam.BeanPropertySqlParameterSource;
import org.springframework.jdbc.core.namedparam.MapSqlParameterSource;
import org.springframework.stereotype.Component;
@Component
("offersDao")
public class OffersDAO {
private JdbcTemplate jdbc;
@Autowired`enter code here`
public void setDataSource(DataSource jdbc) {
this.jdbc = new JdbcTemplate(jdbc);
}
public boolean create(Offer offer) {
BeanPropertySqlParameterSource params = new BeanPropertySqlParameterSource(offer);
return jdbc.update("INSERT INTO offers " + " ( id, name, email, text) "
+ " VALUES " + " ( :id, :name, :email, :text) ", params) == 1;
}
}
// 2nd class // 第二类
package com.caveofprogramming.spring.test;
public class Offer {
private int id;
private String name;
private String email;
private String text;
public Offer() {
}
public Offer(int id, String name, String email, String text) {
this.id = id;
this.name = name;
this.email = email;
this.text = text;
}
public int getId() {
return id;
}
public void setId(int id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public String getEmail() {
return email;
}
public void setEmail(String email) {
this.email = email;
}
public String getText() {
return text;
}
public void setText(String text) {
this.text = text;
}
@Override
public String toString() {
return "Offer [id=" + id + ", name=" + name + ", email=" + email
+ ", text=" + text + "]";
}
}
//3rd main class //第三个主类
package com.caveofprogramming.spring.test;
import java.util.List;
import org.springframework.context.ApplicationContext;
import org.springframework.context.support.ClassPathXmlApplicationContext;
import org.springframework.dao.DataAccessException;
import org.springframework.jdbc.CannotGetJdbcConnectionException;
public class App {
public static void main(String[] args) {
ApplicationContext context = new ClassPathXmlApplicationContext(
"com/caveofprogramming/spring/test/beans/beans.xml");
OffersDAO offersDao = (OffersDAO) context.getBean("offersDao");
try {
Offer offer1 = new Offer(10, "khan", "G@G.com", "GG");
Offer offer2 = new Offer(11, "khan", "M@G.com", "GG");
Offer offer3 = new Offer(12, "khan", "V@G.com", "GG");
offersDao.create(offer1);
offersDao.create(offer2);
offersDao.create(offer3);
} catch (CannotGetJdbcConnectionException ex) {
System.out.println("Unable to connect to database");
} catch (DataAccessException ex) {
System.out.println(ex.getMessage());
System.out.println(ex.getClass());
}
((ClassPathXmlApplicationContext) context).close();
}
}
i tried
public boolean create (Offer offer){
return jdbc.update("insert into offers (firstno,secondno,thirldno) values
( '" +offer.getFirstno() + "', '" +offer.getSecondno() +"' ,'"+offer.getThirldno()+"')")==1;
}
instead of代替
public boolean create(Offer offer) {
BeanPropertySqlParameterSource params = new BeanPropertySqlParameterSource(offer);
return jdbc.update("INSERT INTO offers " + " ( id, name, email, text) "
+ " VALUES " + " ( :id, :name, :email, :text) ", params) == 1;
}
and now it's working that way .现在它就是这样工作的。 Well , it's not answer to me but anyhow this is what i find out to deal with the above error an another way but i still didn't find out what could be the error in the previous query .好吧,这不是我的答案,但无论如何这是我发现的以另一种方式处理上述错误的方法,但我仍然没有发现上一个查询中的错误可能是什么。 thanks to ALL of you friends :) Happy Coding感谢你们所有的朋友 :) 快乐编码
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