会话不会在标签内进行。 PHP会话
[英]Sessions doesn't pass on within tabs. PHP session
问题描述
I'm facing an issue where my simple dummy form doesn't pass it's session variable. 
我遇到的一个问题是我的简单虚拟表单无法通过它的会话变量。 There is an error code 有错误代码
Notice: Undefined index: username in ...login.php on line 8
Notice: Undefined index: password in ...\\login.php on line 9
Wrong username or password 错误的用户名或密码
session start index.php 会话开始index.php
<html>
<head></head>
<body>
<?php session_start();?>
<form action="login.php" method="POST">
Username:<input type="text" name="username">
Password:<input type="password" name="password">
<input type="submit" value="Login">
</form>
</body>
</html>
Validation of the input will be passed on to login.php 输入的验证将传递给login.php
<html>
<head></head>
<body>
<?php
session_start();
$user = "NULL";
$password = "NULL";
$user = $_REQUEST["username"];
$password = $_REQUEST["password"];
if($user == "ali" && $password == "123"){
$_SESSION["$user"] = $user;
echo "Login Successful</br>";
echo '<a href="logout.php">Logout</a>';
}
else{
echo "Wrong username or password</br>";
echo '<a href="index.php">Back</a>';
}
?>
<p>Welcome <?php echo htmlspecialchars($user) ?></p>
</body>
</html>
logout.php logout.php
<html>
<head></head>
<body>
<?php session_start();?>
<form action="login.php" method="POST">
Username:<input type="text" name="username">
Password:<input type="password" name="password">
<input type="submit" value="Login">
</form>
</body>
</html>
1 个解决方案
解决方案1
1 已采纳 2015-10-20 15:17:56
-You are facing Undefined index error because when you directly execute login.php or reload login.php or you open it in another tab, at that time $_REQUEST is an empty array. -您遇到未定义索引错误，因为直接执行login.php或重新加载login.php或在另一个选项卡中打开它时， $_REQUEST是一个空数组。 Actually your coding of login.php is wrong, thats why you are getting Undefined index error. 实际上，您login.php的编码是错误的，这就是为什么您遇到未定义索引错误的原因。
-First of all session_start() must be before <!DOCTYPE html> -首先session_start()必须在<!DOCTYPE html>
- $_SESSION["$user"] is wrong, use $_SESSION['user'] instead. - $_SESSION["$user"]是错误的，请改用$_SESSION['user'] 。
-Why are you using $_REQUEST ? -为什么要使用$_REQUEST ？ Your form method is POST, so use $_POST . 您的表单方法是POST，因此请使用$_POST 。 Refer $_REQUEST vs $_GET and $_POST 参考$ _REQUEST与$ _GET和$ _POST
-Session must be destroyed when user logout. -用户注销时必须销毁会话。
-Here is the working code... -这是工作代码...
1. index.php 1. index.php
<html>
<head></head>
<body>
<form action="login.php" method="POST">
Username:<input type="text" name="username">
Password:<input type="password" name="password">
<input type="submit" value="Login">
</form>
</body>
</html>
2. login.php 2. login.php
<?php session_start(); ?>
<!DOCTYPE html>
<html>
<head>
</head>
<body>
<?php
if( isset($_SESSION['user']) ){
echo 'User is already logged in.<br />';
echo '<a href="logout.php">Logout</a>';
}
else {
if( isset($_POST["username"]) && isset($_POST["password"]) ) {
if($_POST["username"] == "ali" && $_POST["password"] == "123"){
$_SESSION["user"] = $_POST["username"];
echo "Login Successful</br>";
echo '<a href="logout.php">Logout</a>';
}
else {
echo "Wrong username or password</br>";
echo '<a href="index.php">Back</a>';
}
}
}
?>
</body>
</html>
3. logout.php 3. logout.php
<?php
session_start();
?>
<!DOCTYPE html>
<html>
<body>
<?php
// remove all session variables
session_unset();
// destroy the session
session_destroy();
echo "All session variables are now removed, and the session is destroyed."
?>
</body>
</html>
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