[英]Sort Multi-dimensional dictionary
I have a dictionary in the format given below. 我有以下格式的字典。 I want to sort the dictionary based on the value of the "score" values in decreasing order, and in case of a tie, sort in lexicographical order of the "title" value.
我想根据字典中“分数”值的降序对字典进行排序,如果出现平局,则按“书名”值的字典顺序进行排序。
d = {
'123':{
'score': 100,
'title': 'xyz'
},
'234':{
'score': 50,
'title': 'abcd'
},
'567':{
'score': 50,
'title': 'aaa'
}
}
So the output should be: 因此输出应为:
[(100,xyz), (50,aaa), (50,abcd)]
[(100,xyz),(50,aaa),(50,abcd)]
I have tried this: 我已经试过了:
print sorted(d.items(), key=lambda x: (x[1]['score'], x[1]['title']), reverse=True)
But it is sorting in decreasing order for both fields. 但这两个字段的降序排列。
@InsepctorG4dget has it right, since you're only reversing one key, and one key is not (easily) reversible - the way to go is dropping the reverse
and reversing the reversible key: @ InsepctorG4dget正确,因为您只反转一个键,而一个键不是(轻松)可逆的-可行的方法是放弃
reverse
键并反转可逆键:
items = sorted(
d.items(),
# note -x[1]['score'] is negated value
key=lambda x: (-x[1]['score'], x[1]['title'])
)
If you don't mind stable-sorting in-place and modifying a list use list.sort
twice: 如果您不介意就地进行稳定排序和修改列表,请使用
list.sort
两次:
items = d.items()
# last key first
items.sort(key=lambda x: x[1]['title'])
# first key last
items.sort(key=lambda x: x[1]['score'], reverse=True)
Result: 结果:
>>> items
[('123', {'score': 100, 'title': 'xyz'}), ('567', {'score': 50, 'title': 'aaa'}), ('234', {'score': 50, 'title': 'abcd'})]
>>> [(x[1]['score'], x[1]['title']) for x in items]
[(100, 'xyz'), (50, 'aaa'), (50, 'abcd')]
Note that your expected output suggests title
values are not reversed when sorted. 请注意,您的预期输出表明
title
值在排序时不会反转。
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