如何在Ruby中将字符串转换为数组

Question

In ruby, I have an array with an string value:

my_array=["210,207,203,199,169,165,159,152,148,144,140,137"]

How do I convert it into an normal array like this:

my_array=[210,207,203,199,169,165,159,152,148,144,140,137]

Note: all the elements are non-negative values.
I know I can do this by trim the double quote manually, but I am wondering if there is an more elegant way to implement this?

Answer 1

我认为这应该工作：

my_array = my_array[0].split(',').map(&:to_i)

Answer 2

Expanding davidrac's answer, you could also use String#scan instead of String#split :

my_array = my_array[0].scan(/\d+/).map(&:to_i)

EDIT

The benchmarks on this clear show that String#scan is slower:

require 'benchmark'
string = "210,207,203,199,169,165,159,152,148,144,140,137"
Benchmark.bm do |x|
  x.report('split') { 1_000_000.times { string.split(',').map(&:to_i) } }
  x.report('scan') { 1_000_000.times { string.scan(/\d+/).map(&:to_i) } }
end

yields:

           user     system      total        real
split  3.550000   0.010000   3.560000 (  3.580334)
scan   7.350000   0.020000   7.370000 (  7.402508)