如何将未选择的项目从列表移动到另一个？ 列表

Question

I'm trying to move only the unselected items from a List into another List. Also I would like to validate if the items are already on the next list before moving them.

This is what I have so far

 int sel[] = lstNum1.getSelectedIndices();

    for (int i = 0; i < model1.getSize(); i++) {
        if(!model1.getElementAt(i).equals(model1.getElementAt(sel[i]).toString())){
            model2.addElement(model1.getElementAt(i).toString());
        }
    }

I'm trying to compare the item at position "i" with the item at the selectedArray, but no luck.

Answer 1

A simpler version of the answer provided by AbtPst:

    Set<Integer> keepThese = new HashSet<Integer>();
    for (int x : sel) {
      keepThese.add(x);
    }

    for (int i=0 ; i<firstList.size() ; i++) {
       if( !keepThese.contains(i)) {
         if( !secondList.contains(firstList.get(i))) {
           secondList.add(firstList.get(i));
         }
       }
    }

Answer 2

convert your int[] sel to a Set. this will make it easy to check before adding to new list

   Set<Integer> keepThese = new HashSet<Integer>();

    for (int x : sel)
    {
      keepThese.add(x);
    }

    for (int i=0 ; i<firstList.size() ; i++)
    {
       if(keepThese.contains(i))
            continue;

       else
       {
         if(secondList.contains(firstList.get(i)))
           continue;

         else
          secondList.add(firstList.get(i));

       }

  }

now secondList will have all the elements from firstList that are not at indices in the sel array