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符合Equatable的单元测试策略

[英]Unit testing strategy for conforming to Equatable

Let's say I have a struct that conforms to Equatable for my model, something like this: 假设我有一个符合我的模型Equatablestruct ,如下所示:

struct Model: Equatable {
    var a: Int = 0
    var b: String = ""
}

func ==(lhs: Model, rhs: Model) -> Bool {
    return lhs.a == rhs.a && lhs.b == rhs.b
}

Now I write some unit tests for this. 现在我为此写一些单元测试。 Something like: 就像是:

func testModelsAreEqual() {
    let model1 = Model()
    let model2 = Model()
    XCTAssertEqual(model1, model2)
}

func testModelsAreNotEqual1() {
    let model1 = Model()
    var model2 = Model()
    model2.b = "hello world"
    XCTAssertNotEqual(model1, model2)
}

func testModelsAreNotEqual2() {
    let model1 = Model()
    var model2 = Model()
    model2.a = 1
    XCTAssertNotEqual(model1, model2)
}

But how can I write a test that will protect me from the scenario that another property is added to Model without being added to the memberwise-equality check for == like: 但是,如何编写一个测试来保护我免受另一个属性添加到Model情况,而不会添加到==的成员等式检查中:

struct Model: Equatable {
    var a: Int = 0
    var b: String = ""
    var c: Double = 0
}

func ==(lhs: Model, rhs: Model) -> Bool {
    return lhs.a == rhs.a && lhs.b == rhs.b
}

Where obviously my tests will all still pass even though conceptually my Equatable is broken. 很明显我的测试仍然会通过,即使在概念上我的Equatable也被打破了。 Is there a testing strategy I could adopt here that will help alert me to this problem? 我可以采用的测试策略是否有助于提醒我这个问题? Is there something I can do with Swift's Mirror and limited reflection? 有什么东西我可以用斯威夫特的Mirror和有限的反射? Perhaps Mirror.children.count ? 也许Mirror.children.count Or does anyone have a better suggestion? 或者有人有更好的建议吗?

After searching for other solutions, I have decided to use reflection for member count to alert me of changes. 在搜索其他解决方案之后,我决定使用反射进行成员计数以提醒我更改。 Here is the test for the example above: 以下是上述示例的测试:

func testModelStillHas2Members() {
    XCTAssertEqual(Mirror(reflecting: Model()).children.count, 2, "The member count of Model has changed, please check the `==` implementation to ensure all members are accounted for.")
}

This is my take: 这是我的看法:

func testModel3() {
    let model1 = Model()
    var model2 = Model()
    model2.c = 1
    model2.p.name = "Jack"

    let mirror1 = Mirror(reflecting: model1)
    let mirror2 = Mirror(reflecting: model2)

    let prop1 = mirror1.children.reduce([String: NSObject]()) {
        (var dict, e) in
        dict[e.label!] = e.value as? NSObject
        return dict
    }
    let prop2 = mirror2.children.reduce([String: NSObject]()) {
        (var dict, e) in
        dict[e.label!] = e.value as? NSObject
        return dict
    }

    if model1 == model2 {
        XCTAssertEqual(prop1, prop2, "Not really equal")
    } else {
        XCTAssertNotEqual(prop1, prop2, "Not really diffrent")
    }
}

It builds 2 dictionaries with the names & values of all properties in model1 and model2 , then assert if these 2 dictionaries are equal. 它使用model1model2中所有属性的名称和值构建2个字典,然后断言这两个字典是否相等。

Big warning: I have not thoroughly tested this. 大警告:我没有彻底测试过这个。 It worked for the limited number of cases I threw at it. 它适用于我投入的有限数量的案件。 You may have to improvise from here. 你可能需要从这里即兴发挥。

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