跨行反转正则表达式匹配

Question

How would you invert this expression to match everything BUT the contents between the <!-- LIST --> and <!-- /LIST --> tags?

((?s)<!-- LIST -->.*?<!-- /LIST -->)

Meaning I'd like to remove everything before <!-- LIST --> and after <!-- /LIST -->

Answer 1

The regex you have used already matches the section between the two tags, you have to simply add the prior and following sections and use the backreference to replace all the contents with the saved group (usually the slash / is to escape also).

This is a generic regex code:

s/(?s).*(<!-- LIST -->.*?<!-- \/LIST -->).*/\1/

Implementation online here