从shell脚本打开gnome-terminal并保持窗口打开

Question

I'm trying to write a script that sets up my programming environment by taking as an argument the name of the project(directory) I want to open

so for example: ./my_script.sh sample_app

And here is the script so far:

#!/bin/bash

wmctrl -s 0
sublime &
sleep 2

wmctrl -s 1
google-chrome &
sleep 2

wmctrl -s 2
Dir="$echo /home/biTNumb/Projects/ruby/workspace/$1"
echo $Dir
gnome-terminal --window-with-profile=Guard -e ls &
#gnome-terminal -e cd /home/biTNumb/Projects/ruby/workspace/$1 && bundle exec guard &
#gnome-terminal -e cd /home/biTNumb/Projects/ruby/workspace/$1 && rails s &

The problem arises when the script executes:

gnome-terminal --window-with-profile=Guard -e ls &

I get the message The child process exited normally with status 0. :

I can't use the terminal after (I can only close it) and the message hides some part of the output. And yet, I have already created a profile and set the When command exits dropdown menu to 'Hold the terminal open' ...

** I left the comments in the script so you can get the idea of what I'm trying to do

Answer 1

To execute multiple commands in the same gnome-terminal window, use semicolons ; as separators like below:

gnome-terminal -- bash -c "command 1; command 2; ...; bash;"

The last command bash starts the command-line interpreter so that the terminal doesn't exit at the end (use $shell instead of bash for a more general solution).

This way you won't need to define a profile with the option Hold the terminal open when command exits and you won't get the message The child process exited with status 0 (which hide some parts of the output).

Here is what you might write (I use backslashes \\ to split lines):

gnome-terminal -- bash -c \
" ls ;\
cd /home/biTNumb/Projects/ruby/workspace/$1 && bundle exec guard ;\
cd /home/biTNumb/Projects/ruby/workspace/$1 && rails s;\
$bash;"