使用 if(mysql_query) 在多个表中插入数据

Question

I'm beginner in PHP MySQL. I would like ask how can I use this code for INSERT DATA IN MULTIPLE TABLES I will be using this in Single FORM.

Here is my working code for single table:

     if (isset($_POST['btn-signup'])) {
     //table 1
     $variable1 = mysql_real_escape_string($_POST['column1']);
     $variable2 = mysql_real_escape_string($_POST['column2']);
     $variable3 = mysql_real_escape_string($_POST['column3']);
     //table 2
     $var1 = mysql_real_escape_string($_POST['columnT1']);
     $var2 = mysql_real_escape_string($_POST['columnT2']);
     $var3 = mysql_real_escape_string($_POST['columnT3']);



 if(mysql_query("INSERT INTO tableName( column1, column2, column3 )
      VALUES ('$variable1, '$variable2', '$variable3' )"))      
{
  ?>
    <script type="text/javascript">('ADDED SUCCESFULLY!');</script>
  <?php
} else {
?>
  <script type="text/javascript">('Failed!');</script>    
<?php

But I want to add new code for INSERT to another table.
I tried like but still error.

     if(mysql_query("INSERT INTO tableName( column1, column2, column3 )
      VALUES ('$variables', '$variable2', '$variable3' )")

    ("INSERT INTO tableName2( columnT1, columnT2, columnT3 )
      VALUES ('$var1', '$var2, '$var3' )"))

Answer 1

Try This one..

 if(mysql_query("INSERT INTO tableName( column1, column2, column3 )
      VALUES ('$variable1', '$variable2', '$variable3' )"))    // '$variable1' 
{
  ?>
    <script type="text/javascript">alert('ADDED SUCCESFULLY!');</script> // add alert()
  <?php
} else {
?>
  <script type="text/javascript">alert('Failed!');</script>  // add alert()   
<?php }?>

second table :- ("INSERT INTO tableName2( columnT1, columnT2, columnT3 )
  VALUES ('$var1', '$var2, '$var3' )"));

You can Echo the query like

echo  ("INSERT INTO tableName2( columnT1, columnT2, columnT3 )
  VALUES ('$var1', '$var2, '$var3' )")) or die(mysql_error());

or

echo  ("INSERT INTO tableName2( columnT1, columnT2, columnT3 )
  VALUES ('$var1', '$var2, '$var3' )"));

INSERT INTO tableName2( columnT1, columnT2, columnT3 ) VALUES ('var1', 'var2, 'var3' ) // out put

You can check what output generate the query or error an copy the generate query and run in the

phpmyadmin > select database > table > Sql > paste there > Go

if Its not work then tell me

Answer 2

You can just use mysql_query() again

if(mysql_query("INSERT INTO tableName( column1, column2, column3 ) {
  VALUES ('$variable1, $variable2, $variable3' )"))      
    echo 'Success insert into tableName';
} else {
    echo 'Failed insert into tableName';
}

if(mysql_query("INSERT INTO tableName2( columnT1, columnT2, columnT3 )
  VALUES ('$var1, $var2, $var3' )")) {
    echo 'Success insert into tableName2';
} else {
    echo 'Failed insert into tableName2';
}

But its still very procedural, and output here should not be with JS. I suggest you start reading OOP and MVC

Answer 3

You need to add quotes around your values. And use mysql_affected_rows to check you row is inserted or not

<?php

$query1=mysql_query("INSERT INTO tableName( column1, column2, column3)
      VALUES('".$variables."','". $variable2."','". $variable3."')");
$row=mysql_affected_rows();
if($row>0){
    echo "INSERT SUCESSFULLY";
}else{
    echo "ERROR";
}

$query2=mysql_query("INSERT INTO tableName2( columnT1, columnT2, columnT3 )
      VALUES ('".$var1."', '".$var2."', '".$var3."' )");

$row1=mysql_affected_rows();
if($row1>0){
    echo "INSERT SUCESSFULLY";
}else{
    echo "ERROR";
}

Answer 4

May I know the error that you are facing while execute the page can try add mysql_query before second insert query.

mysql_query("INSERT INTO tableName2( columnT1, columnT2, columnT3 )
  VALUES ('$var1, $var2, $var3' )"))

Answer 5

First you have to check to use mysqli or PDO instead of mysql .

$con = mysqli_connect("localhost", "user", "password", "databasename");

Solution 1:

You have to do it in separate mysqli_query calls:

if(mysqli_query($con, "INSERT INTO tableName( column1, column2, column3 ) VALUES ('$variables', '$variable2', '$variable3' )") && mysqli_query($con, "INSERT INTO tableName2( columnT1, columnT2, columnT3 ) VALUES ('$var1', $var2', '$var3' )"))
{
...
}

When using two mysqli_query calls you should take a look at mysql transactions .

Solution 2:

Use mysqli_multi_query :

if(mysqli_multi_query($con, "INSERT INTO tableName2( columnT1, columnT2, columnT3 )
  VALUES ('$var1', '$var2', '$var3'); INSERT INTO tableName2( columnT1, columnT2, columnT3 )
      VALUES ('$var1', $var2', '$var3')"))
{
...
}

When using mysqli you should use mysqli_prepare and mysqli_stmt_bind_param instead of using the php variables directly in your SQL string. This will help you to avoid SQL injection.

Answer 6

You cannot do inserts to multiple tables in one statement. But you can use transactions.

START TRANSACTION;
INSERT INTO tableName (column1,column2,column3) VALUES ('$variable1','$variable2','$variable3');
INSERT INTO tableName2 (column1,column2,column3) VALUES ('$var1','$var2','$var3');
COMMIT;

See: http://dev.mysql.com/doc/refman/5.1/en/commit.html

Answer 7

You can try this, this may seems complicated for you, but it is better :)

<?php

$link = mysqli_connect("localhost", "<username>", "<password>", "<database>");

// Check connection
if($link === false){
    die("ERROR: Could not connect. " . mysqli_connect_error());
}

 if (isset($_POST['btn-signup'])) {

// Your tables here
$tables = array('table1', 'table2', 'table3');

for ($x=0; $x < 3; $x++) {

switch ($x) {
    // Escape user inputs for security and your columns
    case "1":
    $values[$tables[$x]] = array(mysqli_real_escape_string($link, $_POST['column1']), mysqli_real_escape_string($link, $_POST['column2']), mysqli_real_escape_string($link, $_POST['column3']));    
    $columns[$tables[$x]] = array('columnT1', 'columnT2', 'columnT3');
    break;

    case "2":
    $values[$tables[$x]] = array(mysqli_real_escape_string($link, $_POST['columnT1']), mysqli_real_escape_string($link, $_POST['columnT2']), mysqli_real_escape_string($link, $_POST['columnT3'])); 
    $columns[$tables[$x]] = array('columnT1', 'columnT2', 'columnT3');
    break;

    case "3":
    $values[$tables[$x]] = array(mysqli_real_escape_string($link, $_POST['columnT1']), mysqli_real_escape_string($link, $_POST['columnT2']), mysqli_real_escape_string($link, $_POST['columnT3'])); 
    $columns[$tables[$x]] = array('columnT1', 'columnT2', 'columnT3');
    break;
}

// attempt insert query execution
$sql = "INSERT INTO ".$tables[$x]." (".$columns[$tables[$x]][0].", ".$columns[$tables[$x]][1].", ".$columns[$tables[$x]][2].") VALUES ('".$values[$tables[$x]][1]."', '".$values[$tables[$x]][2]."', '".$values[$tables[$x]][3]."')";

if(mysqli_query($link, $sql)){
    echo "Records added successfully for ".$tables[$x].".";
} else{
    echo "ERROR: Could not able to execute $sql. " . mysqli_error($link);
}

}

// close connection
mysqli_close($link);
}
?>