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SQL Server 2008 R2:如何识别和更新十六进制值

[英]SQL Server 2008 R2: How to identify and update hexadecimal value

I have the following table called as Hexa_Table which consists of only one column namely val . 我有下面的表名为Hexa_TableHexa_Table包含一列,即val

Table : Hexa_Table Hexa_Table

CREATE TABLE Hexa_Table
(
 val VARCHAR(50)
);

Insertion : 插入

INSERT INTO Hexa_Table VALUES('123456789101213');
INSERT INTO Hexa_Table VALUES('414F2D53594F545641');
INSERT INTO Hexa_Table VALUES('1234F6789A1213G');
INSERT INTO Hexa_Table VALUES('414F2D363530303035');
INSERT INTO Hexa_Table VALUES('12345678910');

Note : Now I want to update only those values which are Hexadecimal and want to update it to String , for which I need to identify which are the Hexadecimal values in the table. 注意 :现在我想只更新那些Hexadecimal值,并希望将它更新为String ,我需要确定哪些是表中的Hexadecimal值。

For example I have record number 2 that is 414F2D53594F545641 if you convert it will get AO-SYOTVA . 例如,我有记录号2是414F2D53594F545641如果你转换它将获得AO-SYOTVA And in 4th record I have 414F2D363530303035 if you convert it will get AO-650005 . 在第4条记录中我有414F2D363530303035如果你转换它将得到AO-650005

Converted by using : This 通过使用转换:

Questions : 问题
1. How to identify hexadecimal values in the table? 1.如何识别表中的十六进制值?
2. How to update hexadecimal values to string? 2.如何将十六进制值更新为字符串?

You can use CONVERT with style 1 . 您可以将CONVERT与样式1一起使用。 Something like this in your scenario. 你的场景中有类似的东西。

You can use Filter NOT LIKE '%[^0-9a-f]%' to match exact hex pattern and LEN(val) %2 = 0 to check if it has exact number of required bytes for convert 您可以使用Filter NOT LIKE '%[^0-9a-f]%'来匹配精确的十六进制模式,并使用LEN(val) %2 = 0来检查它是否具有convert所需的确切字节数

SELECT  val,
    CAST(CONVERT(varbinary(4), '0x' + val, 1) As VARCHAR(100)) as charstring,
    CONVERT(varbinary(4), '0x' + val, 1) as HexVal
FROM Hexa_Table
WHERE val NOT LIKE '%[^0-9a-f]%'
AND LEN(val) %2 = 0;

Output: 输出:

val charstring  HexVal
414F2D53594F545641  AO-S    0x414F2D53
414F2D363530303035  AO-6    0x414F2D36

Reference 参考

How can I convert a varchar with hexadecimal value to int? 如何将具有十六进制值的varchar转换为int?

MSDN Convert MSDN转换

You can find hexadecimal values in your table using this: 您可以使用以下命令在表中找到十六进制值:

like '%' + CHAR(0x00) +'%'

However in your example which you have shown, the values are stored already as string so I am not sure what you mean to convert the values as string. 但是在您显示的示例中,值已经存储为字符串,因此我不确定将值转换为字符串是什么意思。

On a side note: 在旁注:

If you want to know how to convert the hex to varchar then you need to use CONVERT like this": 如果你想知道如何将十六进制转换为varchar,那么你需要像这样使用CONVERT“:

CONVERT(VARCHAR(MAX), 0x48656c70)

To find out hexadecimal values you can in following: 要查找十六进制值,您可以在以下内容中找到:

select val
from Hexa_Table
where val like '%' + CHAR(0x00) +'%'

It is already stored as VARCHAR , what and how do you want to update? 它已经存储为VARCHAR ,您想要更新的内容和方式?

Try this code: 试试这段代码:

BEGIN TRAN

SELECT * FROM Hexa_Table 
WHERE val = @value_insert

IF (@@ROWCOUNT = 0)
    INSERT Hexa_Table
    SELECT CONVERT(VARCHAR(50), @value_insert)

COMMIT

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