C ++逐行读取但无法逐行显示输出

Question

I am trying to run a C++ code. My input file has number of lines and I am trying remove the spaces in each line and then display. But, when i run the code the output is coming in a single line ie all thelines of the file are being shown in one single line.

Please solve my problem , so that i get the output line by line.

Thanks.

I have tried this code. This is my code:

int main()
{
    int i = 0, len, j;
    std::string str;
    ifstream iFile("g.txt");
    while (std::getline(iFile, str) != 0)
    {
        len = str.length();
        for (i = 0; i < len; i++)
        {
            if (str[i] == ' ')
            {
                for (j = i; j < len; j++)
                {
                    str[j] = str[j + 1];
                }
                len--;
            }
        }
        cout << str;
    }
}

Answer 1

cout<<str; is going to write the string to the output buffer and that is it. The next time you call it the str you write out will start right after that last str that was written. If you want each str on its own line then you can use

cout << str << endl;
//or
cout <<str << "\n";

The reason each line does not retain its newline character is that getline() reads until it encounters a newline and then stores everything up to that newline in the string. It then tosses that newline out instead of adding it to the string.

Answer 2

You are writing like this:

cout<<str;

You need to output the new-line after your string, which is done as follows:

cout<<str<<endl;