Dog.java:16: 错误：不兼容的类型：意外的返回值

Question

Can't figure it out...

class Dog {
  int age;
  public Dog(int dogsAge) {
    age = dogsAge;
  }

  public void bark() {
    System.out.println("Woof!");
  }

  public void run(int feet) {
    System.out.println("Your dog ran " + feet + " feet!");
  }

  public void getAge() {
    return age;
  }

  public static void main(String[] args) {
    Dog spike = new Dog(999);
    spike.bark();
    spike.run(999);
  }

}

I think the error is in the part return age; .

And sorry if i'm not descriptive enough, I am new to Java.

Answer 1

So the variable age is int that returned type should be int instead of void .

public int getAge() {
    return age;
}

void means that no value is returned to caller side.

Answer 2

You need to change your method like this

 public int getAge() {
    return age;
  }

This is a getter method for age . age is of type int in your program,so instead of void ,return int and you will be good. void indicates that this method is not going to return anything.

Answer 3

you can't return a value if the method is void. change your getAge method to return an int.

  public int getAge()
  {
    return age;
  }