[英]Caller Information in Java
In C# we have Caller Information 在C#中,我们有呼叫者信息
public void DoProcessing()
{
TraceMessage("Something happened.");
}
public void TraceMessage(string message,
[System.Runtime.CompilerServices.CallerMemberName] string memberName = "",
[System.Runtime.CompilerServices.CallerFilePath] string sourceFilePath = "",
[System.Runtime.CompilerServices.CallerLineNumber] int sourceLineNumber = 0)
{
System.Diagnostics.Trace.WriteLine("message: " + message);
System.Diagnostics.Trace.WriteLine("member name: " + memberName);
System.Diagnostics.Trace.WriteLine("source file path: " + sourceFilePath);
System.Diagnostics.Trace.WriteLine("source line number: " + sourceLineNumber);
}
// Sample Output:
// message: Something happened.
// member name: DoProcessing
// source file path: c:\Users\username\Documents\Visual Studio 2012\Projects\CallerInfoCS\CallerInfoCS\Form1.cs
// source line number: 31
MSDN Link : CallerInfo MSDN链接: CallerInfo
I want to know Java has equivalent annotations or not ? 我想知道Java是否具有等效的注释?
these features can help us for better tracing 这些功能可以帮助我们更好地跟踪
UPDATE : 更新:
I wrote a class : 我写了一堂课:
public class Trace {
public static void trace() {
StackTraceElement[] stk = Thread.currentThread().getStackTrace();
System.out.println(String.format("LineNumber : %s, ClassName : %s, MethodName : %s, SourceLocation : %s",
stk[1].getLineNumber(), stk[1].getClassName(), stk[1].getMethodName(), stk[1].getFileName())
);
}
}
and Call trace() method : 和调用trace()方法:
public class Main {
public static void main(String[] args) throws Exception {
Trace.trace();
}
}
and RESULT : 和结果:
LineNumber : 8, ClassName : Trace, MethodName : trace, SourceLocation : Trace.java
it is not true for me I want a result like this : 对我来说这不是真的,我想要这样的结果:
LineNumber : 3, ClassName : Main, MethodName : main, SourceLocation : Main.java
In fact I want to now how class and method call my trace() (The Parent) 实际上,我现在想知道类和方法如何调用我的trace()(父类)
You create an exception and print it's stacktrace. 您创建一个异常并打印它的stacktrace。
Exception e = new Exception();
e.printStackTrace();
//or
StackTraceElement[] stack = e.getStackTrace();
StackTraceElement last = stack[0];
EDIT: In the comments Fabian provided a better solution, you don't need to create an exception: 编辑:在Fabian提供了更好的解决方案的注释中,您不需要创建异常:
Thread.currentThread().getStackTrace()
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