阵列分割故障 C

Question

First off, I am not very experienced with C.

I am having to deal with arrays for a problem I need to solve, I have managed to simplify the issue to this:

#include <stdio.h>
#include <string.h>

char array[5] = {"hello"}

int main() {

printf(%s\n", array[0]);

return (0);
}

In this case I am just trying to print the 'h', yet I get a Segmentation Fault.

Answer 1

You have a number of errors to be fixed,

printf(%s\n", array[0]);

Here, you are trying to print a char , try

printf("%c\n", array[0]);

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You are missing a ;

char array[5] = {"hello"}
                         ^

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While declaring a string literal, you don't need the {}

char array[] = "hello";

Answer 2

First of all lets see what %s does - it expects it corresponding to be an address. It starts reading from that address byte by byte as if all these bytes were characters and keeps printing them until it finds the null \\0 character.

Now, char array[5] = {"hello"} means array[0] is 'h' - that's correct. But what's wrong is that you are using %s to print it. So, %s considers 'h' to be an address (well to be precise the ascii value of 'h' as the address). Which is 104 i guess. This can be an address alright but cant be accessed by your normal program (too much details here) and hence the segmentation fault

So, in short use %c to print characters.

Also one thing: array[5] is not enough to hold "hello" - as it is actually 6 characters the sixth is the terminating '\\0' character which is automatically appended to c strings.