[英]Decorators: flask/flask_login, using login_required
I want to use my rendering function both with and without the flask login_required
decorator. 我想在有和没有烧瓶login_required
装饰器的情况下都使用渲染功能。 My attempt was as follows: define the basic function, then assign to a new variable, wrapped with login_required
: 我的尝试如下:定义基本功能,然后分配给一个新的变量,并用login_required
包装:
import pymongo
from flask import render_template
from flask_login import login_required
def base_page(collection='posts'):
db = pymongo.MongoClient().www
title = collection.capitalize()
page = db[collection].find().sort("created", pymongo.DESCENDING)
return render_template('home/home.html', **locals())
base_page_login_required = login_required(base_page)
I then use these in my app.add_url_rule
calls: 然后,在我的app.add_url_rule
调用中使用它们:
app.add_url_rule('/blog', view_func=base_page, defaults={'collection': 'posts'})
app.add_url_rule('/users', view_func=base_page_login_required, defaults={'collection': 'users'})
But obviously I've got something wrong: 但显然我出了点问题:
Traceback (most recent call last):\r, referer: http://localhost/
File "C:/www/flask/wsgi.py", line 26, in <module>\r, referer: http://localhost/
app.add_url_rule('/users', view_func=base_page_login_required, defaults={'collection': 'users'})\r, referer: http://localhost/
File "C:\\bin\\Python34\\lib\\site-packages\\flask\\app.py", line 62, in wrapper_func\r, referer: http://localhost/
return f(self, *args, **kwargs)\r, referer: http://localhost/
File "C:\\bin\\Python34\\lib\\site-packages\\flask\\app.py", line 984, in add_url_rule\r, referer: http://localhost/
'existing endpoint function: %s' % endpoint)\r, referer: http://localhost/
AssertionError: View function mapping is overwriting an existing endpoint function: base_page\r, referer: http://localhost/
Can anyone help me understand this error? 谁能帮助我了解此错误? I assume this is specific to flask and add_url_rule
. 我认为这是特定于flask和add_url_rule
。 I know I could just copy the first function code to a second and use the decorator normally, but I want to follow DRY. 我知道我可以将第一个功能代码复制到第二个并正常使用装饰器,但是我想遵循DRY。
Flask registers routes with an endpoint name; Flask使用端点名称注册路由; you use this name in url_for()
to generate URLs. 您可以在url_for()
使用此名称来生成URL。
By default, Flask uses the name of the function for this, the value of function.__name__
. 默认情况下,Flask为此使用函数名称,即function.__name__
的值。 Assigning a function to another name (even when decorated with a properly constructed decorator), does not give the function object a new name. 将函数分配给另一个名称(即使使用正确构造的装饰器进行装饰)也不会为函数对象提供新名称。
You can use the endpoint
keyword argument to give your second registration a different name instead: 您可以使用endpoint
关键字参数来为您的第二个注册赋予不同的名称:
app.add_url_rule('/blog', view_func=base_page,
defaults={'collection': 'posts'})
app.add_url_rule('/users', view_func=base_page_login_required,
endpoint='users',
defaults={'collection': 'users'})
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