从 url 字符串中，如何获取没有文件名和参数的文件路径

Question

var url = 'http ://domain.com/file.php?id=1'; or

var url = 'https ://domain.com/file.php?id=1'; or

var url = 'https ://domain.com'; or

from either one of these urls I want to get only the path, like the one below:

var path = 'https ://domain.com';

and lastly if the url is

var url = 'https ://domain.com/sg';

i should get

var path = 'https ://domain.com/sg';

Answer 1

You can try this working example. It should work in your case.

https://jsfiddle.net/ch44Lmuk/10/

function getnewUrl(url) {
    url = url.replace("http://", "");
    var index = url.indexOf('/');
    if (index == -1) return url;
    else {
        var split = url.split('/')
        var domain = split[0];
        if (split[1].length == 0) return domain;
        url = url.slice(index);
        index = url.lastIndexOf('.');

        if (index != -1) {
            index = url.lastIndexOf('/');
            url = url.slice(0, index);
        } else {
            index = url.lastIndexOf('/');
            if (index == url.length - 1) url = url.slice(0, index);
        }
        return domain + url;
    }
}