Nooblyf，javascript，由 3 个变量控制的简单循环，不确定为什么它在 1 次迭代后停止循环

Question

Solved! ,

set var looplim = 9

and the overwrite looplim, to looplim = looplim + 8, instead of setting it to infinite, which was continually decreasing in value, which was reducing the value of looplim, but no longer!

learning to code from codecademy in javascript atm, have some experience with python that I need to completely relearn

Ok, so I wanted to create an example of a potential infinite loop, being limited by, multiple variables. This program basically has 3 retained variables that are both increasing in value, 2 of which are added together, the other is squared. Once the squared value gets larger than the added values, the loop stops! For some reason, the loop only runs once, when it should run 7 times, would really appreciate any advice!

http://hastebin.com/noxumojemo.vhdl

var looplim = 1;
var infinite = 8;
var k = 1;

//not sure if I actually need to pass variables to function like this, although, fairly certain i am.
var generator = function(infinite,looplim,k){

    //value of infinite will be slowly increasing, until squared value of k is greater, and subtracted.

    while(infinite >= 8){

        console.log("mobiasMobiasMobias");

        //value of k, is retained, and incremented by 1.

        k = k + 1;

        //looplim increases, by + 8 basically, and is retained.


        looplim = looplim + infinite;


        //loopdestroyer....should be a local variable here, and does not really need to be retained since value k is being passed to it, which is retained.
        loopdestroyer = k*k;


        //new value of infinite is set and retained, the increasing value of looplim, stays above loopdestroyer, for 7 cycles, im pretty sure, unless i'm mathing wrong, looplim being 57, and loopdestroyer being 64, when the loop ends.
        infinite = looplim - loopdestroyer;    
    }
};

generator(infinite,looplim,k);

Answer 1

Unless I'm reading your code wrong, infinite is getting set as 5 in the first loop

var looplim = 1;
var infinite = 8;
var k = 1;

var generator = function(infinite,looplim,k){



   while(infinite >= 8){

      k = k + 1; // k = 2


     looplim = looplim + infinite; // 1 + 8 = 9

     loopdestroyer = k*k;  // k = 2 = 2 * 2 = 4

     infinite = looplim - loopdestroyer;    // 9 - 4  = 5
    }
};

generator(infinite,looplim,k);

Answer 2

At the end of the first loop k is 2 which makes loopdestroyer hold the value 4, looplim is 9 here (4*4 + 1) so looplim - loopdestroyer gives the value 5 with which infinity is set. That makes infinity smaller than 8 so the loop ends.

Please use console.log extensively, it helps.