使用自定义收集器的 Java 8 分组？

Question

I have the following class.

class Person {

    String name;
    LocalDate birthday;
    Sex gender;
    String emailAddress;

    public int getAge() {
        return birthday.until(IsoChronology.INSTANCE.dateNow()).getYears();
    }

    public String getName() {
        return name;
    }
}

I'd like to be able to group by age and then collect the list of the persons names rather than the Person object itself; all in a single nice lamba expression.

To simplify all of this I am linking my current solution that store the result of the grouping by age and then iterates over it to collect the names.

ArrayList<OtherPerson> members = new ArrayList<>();

members.add(new OtherPerson("Fred", IsoChronology.INSTANCE.date(1980, 6, 20), OtherPerson.Sex.MALE, "fred@example.com"));
members.add(new OtherPerson("Jane", IsoChronology.INSTANCE.date(1990, 7, 15), OtherPerson.Sex.FEMALE, "jane@example.com"));
members.add(new OtherPerson("Mark", IsoChronology.INSTANCE.date(1990, 7, 15), OtherPerson.Sex.MALE, "mark@example.com"));
members.add(new OtherPerson("George", IsoChronology.INSTANCE.date(1991, 8, 13), OtherPerson.Sex.MALE, "george@example.com"));
members.add(new OtherPerson("Bob", IsoChronology.INSTANCE.date(2000, 9, 12), OtherPerson.Sex.MALE, "bob@example.com"));

Map<Integer, List<Person>> collect = members.stream().collect(groupingBy(Person::getAge));

Map<Integer, List<String>> result = new HashMap<>();

collect.keySet().forEach(key -> {
            result.put(key, collect.get(key).stream().map(Person::getName).collect(toList()));
});

Current solution

Not ideal and for the sake of learning I'd like to have a more elegant and performing solution.

Answer 1

When grouping a Stream with Collectors.groupingBy , you can specify a reduction operation on the values with a custom Collector . Here, we need to use Collectors.mapping , which takes a function (what the mapping is) and a collector (how to collect the mapped values). In this case the mapping is Person::getName , ie a method reference that returns the name of the Person, and we collect that into a List .

Map<Integer, List<String>> collect = 
    members.stream()
           .collect(Collectors.groupingBy(
               Person::getAge,
               Collectors.mapping(Person::getName, Collectors.toList()))
           );

Answer 2

You can use a mapping Collector to map the list of Person to a list of person names :

Map<Integer, List<String>> collect = 
    members.stream()
           .collect(Collectors.groupingBy(Person::getAge,
                                          Collectors.mapping(Person::getName, Collectors.toList())));

Answer 3

You can also use Collectors.toMap and provide mapping for key, value and merge function(if any).

Map<Integer, String> ageNameMap = 
    members.stream()
            .collect(Collectors.toMap(
              person -> person.getAge(), 
              person -> person.getName(), (pName1, pName2) -> pName1+"|"+pName2)
    );