[英]How can I determine if Java generic implements a particular interface?
How can I determine if a Java generic implements a particular interface? 如何确定Java泛型是否实现特定接口?
I have tried a few different approaches, but they all results in a "cannot find symbol ... variable T" error. 我尝试了几种不同的方法,但它们都导致了“无法找到符号......变量T”的错误。
First Attempt 第一次尝试
public abstract class AbstractClass<T> {
public void doFoo() {
if (T instanceof SomeInterface){
// do stuff
}
}
}
Second Attempt 第二次尝试
public abstract class AbstractClass<T> {
public void doFoo() {
if (SomeInterface.class.isAssignableFrom(T)) {
// do stuff
}
}
}
Add a constructor taking the class of the object. 使用对象的类添加构造函数。
public abstract class AbstractClass<T> {
private Class<T> clazz;
public AbstractClass(Class<T> clazz) {
this.clazz = clazz;
}
public void doFoo() {
if (clazz instanceof SomeInterface){
// do stuff
}
}
}
Add a constraint to the type T
with T extends SomeInterface
, thereby restricting the type T
to be a subtype of SomeInterface
. 向
T
类型添加约束,使用T extends SomeInterface
,从而将类型T
限制为SomeInterface
的子类型。
public abstract class AbstractClass<T extends SomeInterface> {
public void doFoo() {
// do stuff
}
}
Put a bound on it. 绑定它。
public abstract class <T extends SomeInterface> { }
Then you're guaranteed that it will be at least SomeInterface
when passed through as an argument to a method. 然后,当你作为方法的参数传递时,你保证它至少是
SomeInterface
。
From your approach, there's no way to do it, since you don't reference an instance of T
anywhere in your code. 从您的方法来看,没有办法,因为您没有在代码中的任何位置引用
T
的实例。 If you added an argument to it, you'd be able to at least get further. 如果你为它添加了一个参数,你至少可以得到更多。
public void doFoo(T obj) { }
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