如何在C++中的同一行上输入？

Question

i want to input Date in this format 2/11/2015. how can i do this using C++ ? Thanks The following method isn't working.

cin>>day >>month >>year ;

and also user don't have to press enter .

my Code is

#include <iostream>
using namespace std;

class Date
{
private :
    int day,month,year;
    char slash;
public :
    void inputdate(void)
    {
        cout<<"Enter Date in Formate (day/month/year)"<<endl;
        cin >> day >> slash >> month >> slash >> year;
    }
    void checkdate(void)
    {
        if (day<=0 || day>=32)
        {
            cout<<"Day is Wrong ! "<<endl;
        }
        if (month==2 && day>=29)
        {
            cout<<"February can have max 28 days !"<<endl;
        }
        if (month<=0 || month>=13)
        {
            cout<<"Month is wrong !"<<endl;
        }
        if (year<=1799 || year>=3000)
        {
            cout<<"Year is Wrong !"<<endl;
        }
        if ((month==4 || month==6 || month==9 || month==11)&&(day>30))
        {
            cout<<"Day is wrong ! September ,April ,June and November can have maximum 30 days ."<<endl;
        }
    }
    void showdate(void)
    {
        checkdate();
        cout<<"Date is : "<<day<<"/"<<month<<"/"<<year<<endl;
    }
};

Answer 1

C++ does not inherently understand text dates; you will need to either use a library which provides this functionality, or create a function yourself to convert between the text format and the internal integer format (which is generally the number of seconds or milliseconds, depending on platform, since the "Epoch" (00:00 1st January 1970)).

To do this you will need to:

• Collect the date as a single string or character array
• Separate the date into its constituent day/month/year
• Calculate this date as a number of seconds since the Epoch

Having said all this, the first option of using a Library is probably best as it will also contain functions to switch between string and internal date format; which library you choose is up to you and will largely depend on the platform you're coding for.

Answer 2

You can use a dummy char variable to read past the / separator:

int day, month, year;
char slash; // dummy to skip past the '/'

cin >> day >> slash >> month >> slash >> year;