[英]How to go thought multidimensional array?
I have this multidimensional array in php and I need when user is on www.web.com/index?page=graphicdesigner
I read parameter page from get by $_GET["page"
]. 我在php中有此多维数组,当用户在
www.web.com/index?page=graphicdesigner
上时,我需要从$_GET["page"
]的get中读取参数页 。 I need go throught this array and return array under the current position. 我需要遍历此数组并在当前位置返回数组。
So If I am on url above I will get return echo $array["urlanchor"];
因此,如果我在上面的url上,我将得到return
echo $array["urlanchor"];
=> graphic-designer => 图形设计师
$jobs = array(
"graphicdesigner" => array(
"urlanchor" => "graphic-designer",
"og:title" => "graphicdesigner ogtitle",
"og:description" => "graphicdesigner ogdescription",
"og:image" => "",
"og:url" => ""
),
"uidesigner" => array(
"urlanchor" => "ui-designer",
"og:title" => "uidesigner ogtitle",
"og:description" => "uidesigner ogdescription",
"og:image" => "",
"og:url" => ""
)
);
How it is possible? 怎么可能? I can get the correct php code which will be working well.
我可以获得正确的php代码,它将运行良好。
Use the query param as the key to select the array from the multidimensional array: 使用查询参数作为键从多维数组中选择数组:
$jobs = array(
"graphicdesigner" => array(
"urlanchor" => "graphic-designer",
"og:title" => "graphicdesigner ogtitle",
"og:description" => "graphicdesigner ogdescription",
"og:image" => "",
"og:url" => ""
),
"uidesigner" => array(
"urlanchor" => "ui-designer",
"og:title" => "uidesigner ogtitle",
"og:description" => "uidesigner ogdescription",
"og:image" => "",
"og:url" => ""
)
);
$page = $_GET["page"];
$pageArr = $jobs[$page];
echo $pageArr['urlanchor'];
if you have got $jobs
. 如果您有
$jobs
。
$jobs = array(
"graphicdesigner" => array(
"urlanchor" => "graphic-designer",
"og:title" => "graphicdesigner ogtitle",
"og:description" => "graphicdesigner ogdescription",
"og:image" => "",
"og:url" => ""
),
"uidesigner" => array(
"urlanchor" => "ui-designer",
"og:title" => "uidesigner ogtitle",
"og:description" => "uidesigner ogdescription",
"og:image" => "",
"og:url" => ""
)
);
you should use echo $job['graphicdesigner']['urlanchor'] ;
您应该使用
echo $job['graphicdesigner']['urlanchor'] ;
to get the output. 获得输出。
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