[英]Mysql Distinct one column but not every column
I have a table (a list of cars, years and models) and I am trying to show a list of just the years, but the list of years that manufacture has made a car could be huge.我有一张表格(汽车、年份和型号的列表),我试图仅显示年份列表,但是制造商制造汽车的年份列表可能很大。 Meaning when I query "Volvo" Im returning a list of all years Volvo has made a car, Using:
意思是当我查询“沃尔沃”时,我会返回沃尔沃制造汽车的所有年份的列表,使用:
"SELECT id, year FROM `models_auto` WHERE `make`=? ORDER BY `year` DESC;"
However, Volvo may have made 50 cars that year and the return is all 50 duplicate years.然而,沃尔沃那一年可能已经生产了 50 辆汽车,而回报是所有 50 年的重复年份。 I want to return just unique list of years, not duplicates.
我只想返回唯一的年份列表,而不是重复的。 I looked at DISTINCT but using:
我看着 DISTINCT 但使用:
"SELECT DISTINCT id, year FROM `models_auto` WHERE `make`=? ORDER BY `year` DESC;"
Still returns everything because ID is unique.仍然返回所有内容,因为 ID 是唯一的。 How can I only DISTINCT year?
我怎么能只有不同的年份?
Thank you.谢谢你。
If you want only the years then you can use use GROUP BY
.如果您只想要年份,那么您可以使用
GROUP BY
。
SELECT `year`
FROM `models_auto`
WHERE `make`=?
GROUP BY `year`
ORDER BY `year` DESC;"
Or using DISTINCT
:或使用
DISTINCT
:
SELECT DISTINCT `year`
FROM `models_auto`
WHERE `make`=?
ORDER BY `year` DESC;"
One option is to return the years as a comma delimited list, using group_concat()
:一种选择是使用
group_concat()
将年份作为逗号分隔的列表返回:
select make, group_concat(distinct year order by year)
from models_auto
group by make;
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