[英]SWIG C++ List to Java
I am trying to use SWIG to wrap C++ where it defined a LIST of objects like this 我正在尝试使用SWIG来包装C ++,它定义了像这样的对象的LIST
typedef std::list<Country> CountryList;
What exactly do I have to have in the interface file to accomodate for this? 我在接口文件中究竟需要具备什么才能适应这种情况?
Thanks, 谢谢,
Jack 插口
You simply need to add the following to your swig interface file: 您
只需将以下内容添加到swig界面文件中:
%include "std_list.i"
%include "Country.h" /* or declaration of Country */
%template(Country_List) std::list<Country>;
EDIT: I did not know that swig does not provide a std_list.i
for Java to wrap std::list
. 编辑:我不知道swig没有为Java提供
std_list.i
来包装std::list
。 Looking at the one provided for std::vector
, this can be adapted to std::list
. 看一下为
std::vector
提供的那个,这可以适应std::list
。 Note that most functionality is not available, since you really want to use iterators to access list elements. 请注意,大多数功能都不可用,因为您确实希望使用迭代器来访问列表元素。 Anyway, here it goes:
无论如何,这里是:
std_list.i std_list.i
%include <std_common.i>
%{
#include <list>
#include <stdexcept>
%}
namespace std {
template<class T> class list {
public:
typedef size_t size_type;
typedef T value_type;
typedef const value_type& const_reference;
list();
list(size_type n);
size_type size() const;
%rename(isEmpty) empty;
bool empty() const;
void clear();
const_reference back();
%rename(add) push_back;
void push_back(const value_type& x);
void pop_back();
};
}
Instead of wrapping std::list<Country>
, you may instead want to convert this to a corresponding list in Java. 您可能希望将其转换为Java中的相应列表,而不是包装
std::list<Country>
。 For this, however, you need to write appropriate typemaps . 但是,为此,您需要编写适当的类型映射 。
std_list
is not yet in the "Latest Release" (swig-3.0.12) available from the Downloads , but already in the master branch on github . std_list
尚未在“最新版本”(痛饮-3.0.12)可以从下载 ,但已经在GitHub上的主分支 。 You can just download and use ( %include
) it. 您可以下载并使用(
%include
)它。
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