简体   繁体   English

将多个sql查询合并为一个较小且更好的查询

[英]multiple sql queries into one small and better query

I am using these queries in my php page and I think there is a better way to do the same thing. 我在我的php页面中使用这些查询,我认为有一种更好的方法可以做同样的事情。

$cms1 = getRow("select * from cms where cmsID=1");
$cms2 = getRow("select * from cms where cmsID=2");
$cms3 = getRow("select * from cms where cmsID=3");
$cms4 = getRow("select * from cms where cmsID=4");
$cms5 = getRow("select * from cms where cmsID=5");

I am printing the data from these queries like 我正在从这些查询中打印数据

<?=$cms['content']?> 
<?=$cms2['content']?>
<?=$cms3['content']?> ....

Is there a better way to do this or to get all this data in one single query? 是否有更好的方法来执行此操作或在单个查询中获取所有这些数据? I think I might get the result by using AS key in the query but I have no idea how. 我想我可以通过在查询中使用AS键来获得结果,但我不知道如何。

function getRow($query)
{
    $rs = mysql_query($query) or die(mysql_error());
    $result = array();

    if(mysql_num_rows($rs))
    {
        $row = mysql_fetch_assoc($rs);      
        return $row;
    }
}

use mysql IN 使用mysql IN

select * from cms where cmsID in (1,2,3,4,5)

You can use IN clause to replace many OR conditions 您可以使用IN子句替换许多OR条件

$sql = "select * from cms where cmsID in (1,2,3,4,5)";
$result = $conn->query($sql);
if ($result->num_rows > 0) {
    // output data of each row
    while($row = $result->fetch_assoc()) {
    echo $row['cmsID'].' '.$row['content'];//output like  :- 1 content
    }

This can also be best achieved using 这也可以通过使用

BETWEEN 之间

in mysql 在MySQL中

 SELECT * FROM cms WHERE cmsID BETWEEN 1 AND 5; 

For more information on Between clause, you can visit this Link 有关between子句的更多信息,您可以访问此链接

$arrData = array();
$result = mysql_query($query) or die(mysql_error());
while($row = $result->fetch_array()) {

    array_push($arrData,$row);
}

print_r($arrData);

First of All change your function 首先改变你的功能

function getRow($query)
{

$rs = mysql_query($query) or die(mysql_error());
$result = array();
if(mysql_num_rows($rs))
 {

   while($row = mysql_fetch_assoc($rs))
   {
       $record[$row['cmsID']] = $row;
   }

 return $record;
 }
}  

Then change your query 然后更改您的查询

$output = getRow(select * from cms where cmsID in (1,2,3,4,5));  

Then echo your output. 然后回显您的输出。

print_r($output);

for($i=1;$i<=5; $i++) { $cms1 = getRow("select * from cms where cmsID='".$i."'"); for($ i = 1; $ i <= 5; $ i ++){$ cms1 = getRow(“从cms中选择*,其中cmsID ='”。$ i。“'”);

} }

声明:本站的技术帖子网页,遵循CC BY-SA 4.0协议,如果您需要转载,请注明本站网址或者原文地址。任何问题请咨询:yoyou2525@163.com.

 
粤ICP备18138465号  © 2020-2024 STACKOOM.COM