[英]regular expression matching string in scala
I have a string like this我有一个这样的字符串
result: String = /home/administrator/com.supai.common-api-1.8.5-DEV- SNAPPSHOT/com/a/infra/UserAccountDetailsMetaData$.class
/home/administrator/com.supai.common-api-1.8.5-DEV- SNAPSHOT/com/a/infra/UserAccountDetailsMetaData.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/UserAccountMetaData$.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/UserAccountMetaData.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/UserOverridenFunctionMetaDataMetaData$.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/UserOverridenFunctionMetaDataMetaData.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/UserOverridenPermissionMetaData$.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/UserOverridenPermissionMetaData.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/UserRoleMetaData$.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/UserRoleMetaData.class
/home/administrator/com.supai.common-api-1.8.5-DEV- SNAPSHOT/com/a/infra/VendorAddressMetaData$.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/VendorAddressMetaData.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/reactore/infra/VendorContactMetaData$.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/reactore/infra/VendorContactMetaData.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/reactore/infra/VendorMetaData$.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/VendorMetaData.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/WeekMetaData$.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/WeekMetaData.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/WorkflowMetadataMetaData$.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/WorkflowMetadataMetaData.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/WorkflowNotificationMetaData$.class
/home/administrator/com.supai.common-api-1.8.5-DEV-SNAPSHOT/com/a/infra/WorkflowNotificationMetaData.class
/home/a/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
/home/a/usr/share/common-api/lib/com.supai.common-api-1.8.5-DEV-SNAPSHOT.jar
/home/common/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
/home/raghav/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
/home/sysadmin/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
/home/tmp/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
/home/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
/home/usr/share/common-api/lib/com.supai.common-api-1.8.5-DEV-SNAPSHOT.jar
/usr/share/common-api/lib/com.supai.common-api-1.8.5-DEV-SNAPSHOT.jar
regex: scala.util.matching.Regex = (\\/([u|s|r])\\/([s|h|a|r|e]))
x: scala.util.matching.Regex.MatchIterator = empty iterator`
and out of this how can I get only this part /usr/share/common-api/lib/com.supai.common-api-1.8.5-DEV-SNAPSHOT.jar
and this part can be anywhere in the string, how can I achieve this, I tried using regular expression in Scala but don't know how to use forward slashes, so anybody plz explain how to do this in scala.我怎么能只得到这部分
/usr/share/common-api/lib/com.supai.common-api-1.8.5-DEV-SNAPSHOT.jar
这部分可以在字符串中的任何地方,如何我能做到这一点吗,我尝试在 Scala 中使用正则表达式,但不知道如何使用正斜杠,所以请任何人解释如何在 Scala 中执行此操作。
What is your search criteria?您的搜索条件是什么? Your pattern seems to be wrong.
你的模式似乎是错误的。 In your rexexp, I see
u|s|r
which means to search for either u
, or s
or r
.在您的 rexexp 中,我看到
u|s|r
表示搜索u
或s
或r
。 See here for more information请参阅此处了解更多信息
how can I get only this part /usr/share/common-api/lib/com.supai.common-api-1.8.5-DEV-SNAPSHOT.jarand this part can be anywhere in the string
我怎么能只得到这部分 /usr/share/common-api/lib/com.supai.common-api-1.8.5-DEV-SNAPSHOT.jarand 这部分可以在字符串中的任何地方
If you are looking for a path, see the below example:如果您正在寻找路径,请参见以下示例:
scala> val input = """/home/common/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
| /home/raghav/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
| /home/sysadmin/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
| /home/tmp/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
| /home/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
| /home/usr/share/common-api/lib/com.supai.common-api-1.8.5-DEV-SNAPSHOT.jar
| /usr/share/common-api/lib/com.supai.common-api-1.8.5-DEV-SNAPSHOT.jar"""
input: String =
/home/common/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
/home/raghav/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
/home/sysadmin/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
/home/tmp/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
/home/usr/share/common-api/lib/com.supai.common-api-1.3-SNAPSHOT.jar
/home/usr/share/common-api/lib/com.supai.common-api-1.8.5-DEV-SNAPSHOT.jar
/usr/share/common-api/lib/com.supai.common-api-1.8.5-DEV-SNAPSHOT.jar
scala> val myRegExp = "/usr/share/common-api/lib/com.supai.common-api-1.8.5-DEV-SNAPSHOT.jar".r
myRegExp: scala.util.matching.Regex = /usr/share/common-api/lib/com.supai.common-api-1.8.5-DEV-SNAPSHOT.jar
scala> val myRegExp2 = "helloWorld.jar".r
myRegExp2: scala.util.matching.Regex = helloWorld.jar
scala> (myRegExp findAllIn input) foreach( println)
/usr/share/common-api/lib/com.supai.common-api-1.8.5-DEV-SNAPSHOT.jar
/usr/share/common-api/lib/com.supai.common-api-1.8.5-DEV-SNAPSHOT.jar
scala> (myRegExp2 findAllIn input) foreach( println)
scala>
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