php - 提取括号、单引号和双引号之间的文本

Question

I want to extract text between parenthesis, single quotes and double quotes. I have made it for single and double quotes, but I cant make it for the third parameter, parenthesis:

for example:

<img src="/path/to/the/file.jpg"></div>
<img src='/path/to/the/file2.png'></div>
<div style="background:url(/path/to/the/file555.gif)"></div>

I want to extract:

/path/to/the/file.jpg
/path/to/the/file2.png
/path/to/the/file555.gif

and this is the regex expression I am using:

preg_match_all('/(["\'])(.*(?:\.jpg|\.png|\.gif))\1/m', $subject, $matches)

or even this one:

preg_match_all('/(["\'])([^"\']*(?:\.jpg|\.png|\.gif))\1/m', $subject, $matches)

Answer 1

(?<=['"\(])[^"())\n']*?(?=[\)"'])

You can use this.See demo.

https://regex101.com/r/cD5jK1/12

$re = "/(?<=['\"\\(])[^\"()\\n']*?(?=[\\)\"'])/m"; 
$str = "<img src=\"/path/to/the/file.jpg\"></div>\n<img src='/path/to/the/file2.png'></div>\n<div style=\"background:url(/path/to/the/file555.gif)\"></div>"; 

preg_match_all($re, $str, $matches);

Answer 2

您还可以使用正则表达式：

[\"\'\(]+(\/[^\/]+\/[^\/]+\/[^\/]+\/[^\.]+\.(?:jpg|gif|png))[\)\"\']+