Jquery UI按钮功能在弹出对话框打开时执行

Question

This is my Code, after popup dialog box open need to click the button the function given should work.

$(document).ready(function () {
            var box = $('#openbox').dialog({
                autoOpen: false,
                width: 100,
                height: 200,
                title: 'hi',
                modal: true
            });
            $('#open-box').click(function () {
                getbtn = $('#openbox').dialog({
                    buttons: {
                        "view": sayhi()
                    }
                });
                getbtn.dialog("open");
            });
            function sayhi() {
                alert("hi..");
            }
        });

But problem is while opening popup dialog box the function sayhi() is working. not showing any name in button and button click in popup box not working. how to do this?

Answer 1

You can not call function like that because

"view"://here you have  object which have method view 

To call that try

getbtn.button.view 

and to call directory just use this

"view": sayhi();