[英]Unable to display extracted data from API into HTML form
I started using the AlchemyAPI key to extract json/xml data from url's. 我开始使用AlchemyAPI密钥从URL提取json / xml数据。 The alchemy url api key works just great when entered along with the queried url but I wanted the url part to come from the user side so first I created a form with the following code:
炼金术URL api密钥与查询的URL一起输入时效果很好,但是我希望url部分来自用户端,因此首先我用以下代码创建了一个表单:
<form method="post" class="SearchCSS" action="/NENSearch.php?go" id="categorizer">
<h1>Enter your Queries</h1>
<input type="text" name="Search" placeholder="Enter the article URL">
<input type="submit" value="Search">
</form>
Then using PHP passed the user's submitted url into the endpoint of the alchemy api and stored the json data into a variable and later displayed the parsed data using the following code (Problem: Code actually doesn't display anything): 然后使用PHP将用户提交的url传递到alchemy api的端点中,并将json数据存储到变量中,然后使用以下代码显示已解析的数据(问题:代码实际上不显示任何内容):
<?php
echo "this works here";
if(isset($_POST['submit'])){
if(isset($_GET['go'])){
if(preg_match("%^((http?://)|(www\.))([a-z0-9-].?)+(:[0-9]+)?(/.*)?$%i", $_POST['Search'])){
$url=$_POST['Search'];}
echo $url;}
$response = file_get_contents("http://gateway-a.watsonplatform.net/calls/url/URLGetCombinedData?extract=page-image,entity,keyword,taxonomy&apikey=1f324507a9d516d9429e14f970ccc83de9df2&showSourceText=1&sentiment=1&outputMode=json"ations=1&url='.$url.'");
$response = json_decode($response);
echo $response;}
echo "<br/> this is not working";
?>
The basic alchemyAPI url I used looks like this (drupal url added at the end) : http://access.alchemyapi.com/calls/url/URLGetRankedTaxonomy?apikey=1f324507a9d51694a29e14f970ccc83de9df2&outputMode=jsonp&knowledgeGraph=1&extract=taxonomy&url=https://www.drupal.org/node/2148541 我使用的基本alchemyAPI url看起来像这样(末尾添加了重复的url): http ://access.alchemyapi.com/calls/url/URLGetRankedTaxonomy?apikey=1f324507a9d51694a29e14f970ccc83de9df2&outputMode=jsonp&knowledgeGraph=1&extract=**taxonomy 。 drupal.org/node/2148541
I just started working with API's and Any help in displaying the parsed json data into html form will be of great help. 我刚刚开始使用API,并且将解析后的json数据显示为html形式的任何帮助都会有很大帮助。 Thanks in advance.
提前致谢。 :)
:)
"(Problem: Code actually doesn't display anything)"
“(问题:代码实际上不显示任何内容)”
That's because everything that's inside this conditional statement will not execute: 这是因为该条件语句中的所有内容都不会执行:
if(isset($_POST['submit'])){...}
Due to the fact that there isn't an input bearing the "submit" name attribute. 由于没有输入带有“提交”名称属性的事实。
What you need to do is to name your submit's input: 您需要做的就是命名提交者的输入:
<input name="submit" type="submit" value="Search">
Had error reporting been set to catch and display on your system, would have thrown an undefined index submit notice. 如果已将错误报告设置为在系统上捕获并显示,则将引发未定义的索引提交通知。
Reference: 参考:
Also make sure that $_GET['go']
is populating correctly. 还要确保
$_GET['go']
正确填充。 Error reporting will also let you know if it is or isn't. 错误报告还会使您知道是否存在。
Sidenote: 边注:
Having used an else{...}
against your opening if{...}
conditional statement, would have fired up. if{...}
条件声明中使用了else{...}
不是您的开头,则可能会触发。
You should also check against $_POST['Search']
for content, if it's set or not empty. 您还应该检查
$_POST['Search']
的内容(如果设置为空)。
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