[英]Mysql Column 'nume' in field list is ambiguous error
select nume as "Nume", adresa as "Adresa",localitate as "Localitatea"
from info
left join angajati
on id_i = id_a
where localitate like "Orhei"
and year(curdate()) - year(data_nast) >=50
I have 2 tables with nume field and i'm getting the error, please help i don't now why this code didn't work !!! 我有2个带有nume字段的表,但出现了错误,请帮助我现在不理解为什么此代码不起作用!
You need to define which table the nume
field should be coming from. 您需要定义nume
字段应来自哪个表。 Here's one way using a table alias: 这是使用表别名的一种方法:
select i.nume as "Nume",
adresa as "Adresa",
localitate as "Localitatea"
from info i
left join angajati a on id_i = id_a
where localitate like "Orhei"
and year(curdate()) - year(data_nast) >=50
When using joins
, if the same field is represented in multiple tables, you have to define which table you are referring to. 使用joins
,如果在多个表中表示相同的字段,则必须定义要引用的表。
Since you are joining on the id_i
and id_a
columns, the two nume
columns are distinct in the joined result. 由于您要在id_i
和id_a
列上进行id_i
,因此两个nume
列在联接结果中是不同的。 Specify which table's nume
column you mean: 指定您要表示的表的nume
列:
SELECT info.nume AS "Nume" ...
or 要么
SELECT angajati.nume AS "Nume" ...
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