Python 中的十进制到二进制半精度 IEEE 754

Question

I was only able to convert a decimal into a binary single-precision IEEE754, using the struct.pack module, or do the opposite (float16 or float32) using numpy.frombuffer

Is it possible to convert a decimal to a binary half precision floating point, using Numpy?

I need to print the result of the conversion, so if I type "117.0" , it should print "0101011101010000"

Answer 1

if I type "117.0", it should print "0101011101010000"

>>> import numpy as np
>>> bin(np.float16(117.0).view('H'))[2:].zfill(16)
'0101011101010000'

.view('H') reinterprets the memory occupied by the float16 value as an unsigned integer.

Answer 2

Mark Dickinson建议的float16方法必须跟在tostring()方法之后才能获得所需的二进制表示：

data = numpy.float16(2.3).tostring()