在php中显示表中的数据

Question

$sql=" SELECT * from `request_location` where requestid = '".$requestid."' ";
    $result = mysqli_query($con, $sql);
    if(mysqli_num_rows($result)>0)
        {
            echo "(";
            while($row = mysqli_fetch_assoc($result))
                {
                    echo  $row["location_tag"]; 
                    echo ",";
                }
            echo ")";   
        }

I have this above code that displays data in a format where the result is placed within round brackets and each term is separated by a comma

The result that i am getting is like this

(a,b,c,)

Although it seems to be fine but i want that the comma should not appear after c as it is the last term like this

(a,b,c)

Can anyone please tell how to remove comma after the last element

Answer 1

Try this use PHP str_replace :-

$str='(a,b,c,)';
str_replace(",)",")",$str);

Demo

or try this code :-

$var= "(";
while($row = mysqli_fetch_assoc($result))
{
$var.=  $row["location_tag"]; 
$var.= ",";
}
$var.= ")";  
echo str_replace(",)",")",$var);

Answer 2

Solution 1:

You can do it using implode() function and array().

Logic behind it:

1) Take a blank array.

2) Fetch the results the same way as existing.

3) Append results to the array.

4) After the loop ends implode() the array with a comma.

5) Add a prepending and post pending ( and ) to the result.

sql=" SELECT * from `request_location` where requestid = '".$requestid."' ";
$result = mysqli_query($con, $sql);
$arr = array();
if(mysqli_num_rows($result)>0) {
  while($row = mysqli_fetch_assoc($result)) {
    $arr[] = ["location_tag"]; 
  }
}
echo ! empty($arr) ? '(' . implode(',', $arr) . ')' : '';

Solution 2:

Use MYSQL's GROUP_CONCAT() (if you want to fetch only one field from database table).

sql=" SELECT GROUP_CONCAT(location_tag) from `request_location` where requestid = '".$requestid."' ";
    $result = mysqli_query($con, $sql);
    $ids = '';
    if(mysqli_num_rows($result)>0) {
      while($row = mysqli_fetch_assoc($result)) {
        $ids = ["location_tag"]; 
      }
    }

echo ! empty($ids) ? '(' . $ids . ')' : '';

Answer 3

Use an IF condition and check the num_of_rows

$sql=" SELECT * from `request_location` where requestid = '".$requestid."' ";
$result = mysqli_query($con, $sql);
$count = mysqli_num_rows($result);
if($count>0)
    {
        echo "(";
        $i = 1;
        while($row = mysqli_fetch_assoc($result))
            {
                echo  $row["location_tag"];
                if($i<$count) {
                 echo ",";
                }
              $i++;

            }
        echo ")";   
    }

Answer 4

what about this

$sql= "SELECT * from request_location where requestid = '$requestid'";
$result = mysqli_query($con, $sql);
if(mysqli_num_rows($result)>0)
    {
        $new = ''
        while($row = mysqli_fetch_assoc($result))
        {
            $new .=  $row["location_tag"].",";
        }            

        $data =  "(".$new.")"; // Output - (a,b,c,)
        $new_data = str_replace(",)", ")", $data);
        echo $new_data ; // Output - (a,b,c)

    }

Answer 5

For adding "," between two string you can use implode(",", array_variable) , like below:

$sql=" SELECT * from `request_location` where requestid = '".$requestid."' ";
$result = mysqli_query($con, $sql);
if(mysqli_num_rows($result)>0)
    {
        while($row = mysqli_fetch_assoc($result))
            {
                $location_tag_arr[] = $row["location_tag"];
            }
        echo ")";   
    }

echo "(" . implode(",", $location_tag_arr) . ")";
//^output will be: (a,b,c)