如何从特定元素获取图像src

Question

My sample html section with several items like this:

<ul class="catalog">
  <li class="catalog_item catalog_item--default-view">
    <div class="catalog_item_image">
      <img src="/img/01.png" alt="model01" class="catalog_item_icons__big-foto">
   </div>
   <ul class="catalog_item_icons">
      <li class="catalog_item_icons__preview"><img src="/img/01-01.png" alt="01" class="catalog_item_icons__preview--foto-small"></li>
      <li class="catalog_item_icons__preview"><img src="/img/01-02.png" alt="02" class="catalog_item_icons__preview--foto-small"></li>
      <li class="catalog_item_icons__preview"><img src="/img/01-03.png" alt="03" class="catalog_item_icons__preview--foto-small"></li>
   </ul>

I want to change src of img.catalog_item_icons__big-foto with src of img.catalog_item_icons__preview--foto-small

after clicking on li element only in it's parent ul.catalog.

That was my try:

$(".catalog_item_icons__preview").each(function () {
  $(this).on("click", function() {
    console.log('Clicked preview!');
    // get image fileName
    var smallImagePath = $(this).children("img").attr("src");
    console.log("small image: " + smallImagePath);
    var $bigPreview = $(this).closest('img.catalog_item_icons__big-foto').attr("src");

    // print in console src of nearest big image
    console.log($bigPreview);

  });

});

I can get the src of small image, but can't even read the src of the img above in tree. Output in console: undefined. Don't understand why :(

Answer 1

Use this script:

$(document).ready(function() {
    //It is executing a function when it is clicked on an item
    $('.catalog_item_icons li').click(function() {
        //Taking the source of the image of the clicked element.
        //with $('img', this) you are choosing the the image in the clicked element
        _src = $('img', this).attr('src');
        //In the next line I am assigning to the _obj variable - the parent .catalog_item--default-view of the clicked element
        _obj = $(this).parents('.catalog_item--default-view');
        //In the next line i am changing the source attribute of the .catalog_item_icons__big-foto located in the _obj object
        $('.catalog_item_icons__big-foto', _obj).attr('src', _src);
    });
});

Answer 2

catalog_item_icons__big-foto is not a direct ancestor so closest will not find it. The closest metod looks at itself and than looks at parents. The element you are looking for is not a parent, it is a child of one of those parents.

Easiest thing is to look for the top li and find the image from there.

$(this).closest(".catalog_item catalog_item--default-view")
    .find('img.catalog_item_icons__big-foto')

or option is to find the parent ul and find the previous sibling and than find the image.

Answer 3

problem is here The closest() method returns the first ancestor of the selected element.An ancestor is a parent, grandparent, great-grandparent, and so on.

 var $bigPreview = $(this).closest('img.catalog_item_icons__big-foto').attr("src");

you just use class that will work for you

 var $bigPreview = $('img.catalog_item_icons__big-foto').attr("src");

Answer 4

This may help you, check console following code is working for me

$("li.catalog_item_icons__preview").on("click", function(){
    // get image fileName
    var smallImagePath = $(this).children("img").attr("src");
    console.log("small image: " + smallImagePath);
    var bigPreview = $(this).parent('ul').siblings(".catalog_item_image").children(".catalog_item_icons__big-foto").attr("src");

    // print in console src of nearest big image
    console.log(bigPreview);
});

 $("li.catalog_item_icons__preview").on("click", function(){ // get image fileName var smallImagePath = $(this).children("img").attr("src"); console.log("small image: " + smallImagePath); var bigPreview = $(this).parent('ul').siblings(".catalog_item_image").children(".catalog_item_icons__big-foto").attr("src"); // print in console src of nearest big image console.log(bigPreview); });

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <ul class="catalog"> <li class="catalog_item catalog_item--default-view"> <div class="catalog_item_image"> <img src="/img/01.png" alt="model01" class="catalog_item_icons__big-foto"> </div> <ul class="catalog_item_icons"> <li class="catalog_item_icons__preview"><img src="/img/01-01.png" alt="01" class="catalog_item_icons__preview--foto-small"></li> <li class="catalog_item_icons__preview"><img src="/img/01-02.png" alt="02" class="catalog_item_icons__preview--foto-small"></li> <li class="catalog_item_icons__preview"><img src="/img/01-03.png" alt="03" class="catalog_item_icons__preview--foto-small"></li> </ul> </li> </ul>

Answer 5

Try this

 $(".catalog_item_icons__preview").click(function() { $(".catalog_item_icons__big-foto").attr("src", $(this).children("img").attr("src")); console.log($(".catalog_item_icons__big-foto").attr("src")); });

 <script src="http://gh-canon.github.io/stack-snippet-console/console.min.js"></script> <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <div class="catalog_item_image"> <img src="/img/01.png" alt="model01" class="catalog_item_icons__big-foto"> </div> <ul class="catalog_item_icons"> <li class="catalog_item_icons__preview"> <img src="/img/01-01.png" alt="01" class="catalog_item_icons__preview--foto-small"> </li> <li class="catalog_item_icons__preview"> <img src="/img/01-02.png" alt="02" class="catalog_item_icons__preview--foto-small"> </li> <li class="catalog_item_icons__preview"> <img src="/img/01-03.png" alt="03" class="catalog_item_icons__preview--foto-small"> </li> </ul>