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从“ std :: istringstream”初始化“ const std :: string”

[英]Initializing “const std::string” from “std::istringstream”

I'm trying to parse a file which is in Key<whitespace>Value format. 我正在尝试解析Key<whitespace>Value格式的文件。 I'm reading the file lines in an std::istringstream object, and I'm extracting a Key string from it. 我正在读取std::istringstream对象中的文件行,并std::istringstream提取Key字符串。 I want to avoid accidentally changing the value of this Key string by making it const . 我想通过使它成为const来避免意外更改此Key字符串的值。

My best attempt was initializing a temporary VariableKey object, and then making a constant one out of it. 我最好的尝试是初始化一个临时的VariableKey对象,然后从中创建一个常量。

std::ifstream FileStream(FileLocation);
std::string FileLine;
while (std::getline(FileStream, FileLine))
{
    std::istringstream iss(FileLine);
    std::string VariableKey;
    iss >> VariableKey;
    const std::string Key(std::move(VariableKey));

    // ...
    // A very long and complex parsing algorithm
    // which uses `Key` in a lot of places.
    // ...
}

How do I directly initialize a constant Key string object? 如何直接初始化常量Key字符串对象?

It's arguably better to separate file I/O from processing, and instead of creating a const Key inside the same function - call a line-processing function that takes a const std::string& key parameter. 可以说最好将文件I / O与处理分开,而不是在同一函数中创建const Key调用带有const std::string& key参数的行处理函数。

That said, if you want to continue with your current model, you can simply use: 就是说,如果您想继续使用当前模型,则可以简单地使用:

const std::string& Key = VariableKey;

There's no need to copy or move anything anywhere. 无需在任何地方复制或移动任何内容。 Only const std::string members functions will be accessible via Key . 通过Key只能访问const std::string成员函数。

You can avoid the "scratch" variable by extracting the input into a function: 您可以通过将输入提取到函数中来避免“ scratch”变量:

std::string get_string(std::istream& is) 
{
    std::string s;
    is >> s;
    return s;
}

// ...

while (std::getline(FileStream, FileLine))
{
    std::istringstream iss(FileLine);
    const std::string& Key = get_string(iss);

// ...

(Binding the function's result to a const reference extends its lifetime.) (将函数的结果绑定到const引用可延长其寿命。)

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