Shell脚本（分配给变量）不起作用

Question

#!/bin/bash
if [ -f "$1" ] #parameter is file name, if i exists...
then
    VARIABLE=`cat "$1"` #assign what's inside into VARIABLE
fi

I've tried bash -x script_01.sh "file" and the tracing works:

+ '[' -f file ']'
++ cat file
+ VARIABLE='Wednesday, November  4, 2015 04:45:47 PM CET'

But the problem is that when I echo $VARIABLE, it's empty. Do you guys have any tips on how to make it work? Thank you.

Answer 1

VARIABLE is set in the process that runs the script, not the process which called the script. If you want to set it in your current environment, you need to source the file instead.

. script_01.sh "file"