[英]Detecting Java VM architecture on Windows 10
I have following piece of code to detect if my app is running on 64-bit platform: 我有以下代码来检测我的应用程序是否在64位平台上运行:
public static boolean is64BitVM() {
String bits = System.getProperty("sun.arch.data.model", "?");
logger.debug(String.format("sun.arch.data.model=%s", bits));
if (bits.equals("64")) {
return true;
}
String java_vm_name = System.getProperty("java.vm.name");
logger.debug(String.format("java.vm.name=%s", java_vm_name));
String os_arch = System.getProperty("os.arch");
logger.debug(String.format("os.arch=%s", os_arch));
if (bits.equals("?")) {
// probably sun.arch.data.model isn't available
// maybe not a Sun JVM?
// try with the vm.name property
return java_vm_name.toLowerCase().indexOf("64") >= 0;
}
// probably 32bit
return false;
}
It used to run nicely on Windows 7, but after upgrade to Windows 10 the same piece of code started to report 32bit architecture: 它曾经在Windows 7上运行良好,但是升级到Windows 10后,同一段代码开始报告32位体系结构:
2015-11-05 17:53:15,429 DEBUG [javawsApplicationMain] sun.arch.data.model=32
2015-11-05 17:53:15,431 DEBUG [javawsApplicationMain] java.vm.name=Java HotSpot(TM) Client VM
2015-11-05 17:53:15,431 DEBUG [javawsApplicationMain] os.arch=x86
What is strange is that it reports 32-bit architecture when run through JWS, but when I run it locally in my IDE I get proper result (64-bit). 奇怪的是,当通过JWS运行时,它报告32位体系结构,但是当我在IDE中本地运行它时,会得到正确的结果(64位)。 Seems to be another freaking issue with Windows 10 security model.
Windows 10安全模型似乎是另一个令人毛骨悚然的问题。 Any thoughts?
有什么想法吗?
The solution that worked was to uninstall 32-bit version and then install latest 64-bit Java. 有效的解决方案是卸载32位版本,然后安装最新的64位Java。 At first I have installed Java 8 but I could not force my JWS app to be launched (even adding self-signed cert to exceptions as well as URL from .jnlp file did not help).
最初,我已经安装了Java 8,但无法强制启动JWS应用程序(即使将自签名证书添加到异常以及.jnlp文件中的URL也无济于事)。 Eventually installed latest Java 7 and that did the trick.
最终安装了最新的Java 7,并且成功了。
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