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使用async / await时防止winforms UI阻止

[英]Prevent winforms UI block when using async/await

I'm fairly new to async/await programming and sometimes I feel that I understand it, and then all of a sudden something happens and throws me for a loop. 我对async / await编程很新,有时候我觉得我理解它,然后突然发生了一些事情,并引发了我的循环。

I'm trying this out in a test winforms app and here is one version of a snippet that I have. 我在测试winforms应用程序中尝试这个,这是我的一个版本的片段。 Doing it this way will block the UI 这样做会阻止UI

private async void button1_Click(object sender, EventArgs e)
{

    int d = await DoStuffAsync(c);

    Console.WriteLine(d);

}

private async Task<int> DoStuffAsync(CancellationTokenSource c)
{

        int ret = 0;

        // I wanted to simulator a long running process this way
        // instead of doing Task.Delay

        for (int i = 0; i < 500000000; i++)
        {



            ret += i;
            if (i % 100000 == 0)
                Console.WriteLine(i); 

            if (c.IsCancellationRequested)
            {
                return ret;
            }
        }
        return ret;
}

Now, when I make a slight change by wrapping the body of "DoStuffAsync()" in a Task.Run it works perfectly fine 现在,当我通过在Task.Run中包装“DoStuffAsync()”的主体进行轻微更改时,它的工作完全正常

private async Task<int> DoStuffAsync(CancellationTokenSource c)
    {
        var t = await Task.Run<int>(() =>
        {
            int ret = 0;
            for (int i = 0; i < 500000000; i++)
            {



                ret += i;
                if (i % 100000 == 0)
                    Console.WriteLine(i);

                if (c.IsCancellationRequested)
                {
                    return ret;
                }
            }
            return ret;

        });


        return t;
    }

With all that said, what is the proper way to handle this scenario? 尽管如此,处理这种情况的正确方法是什么?

When you write such code: 当你写这样的代码时:

private async Task<int> DoStuffAsync()
{
    return 0;
}

This way you are doing things synchronously, because you are not using await expression. 这样你就可以同步处理,因为你没有使用await表达式。

Pay attention to the warning: 注意警告:

This async method lacks 'await' operators and will run synchronously. 这种异步方法缺少“等待”运算符并将同步运行。 Consider using the 'await' operator to await non-blocking API calls, or 'await Task.Run(...)' to do CPU-bound work on a background thread. 考虑使用'await'运算符等待非阻塞API调用,或'await Task.Run(...)'在后台线程上执行CPU绑定工作。

Based on the warning suggestion you can correct it this way: 根据警告建议,您可以这样纠正:

private async Task<int> DoStuffAsync()
{
    return await Task.Run<int>(() =>
    {
        return 0;
    });
}

To learn more about async/await you can take a look at: 要了解有关async / await的更多信息,您可以查看:

You just need to change the DoStuffAsync task little bit, as below. 您只需稍微更改DoStuffAsync任务,如下所示。

private async Task<int> DoStuffAsync(CancellationTokenSource c)
{
     return Task<int>.Run(()=> {
            int ret = 0;

            // I wanted to simulator a long running process this way
            // instead of doing Task.Delay

            for (int i = 0; i < 500000000; i++)
            {



                ret += i;
                if (i % 100000 == 0)
                    Console.WriteLine(i);

                if (c.IsCancellationRequested)
                {
                    return ret;
                }
            }
            return ret;
        });
}

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