函数指针返回 C 中某种类型的指针

Question

I am having trouble solving this below piece of code.

When i compile the entire file with this below piece of code included, i see a warning ( shown below), which i don't see if excluded from the entire *.c file.

CODE:

int * ( * get_ptr1)(int) = (int* )0x234456;
printf("The address of the func_ptr is %x\n", get_ptr1);

Warning message:

Initialization from incompatible pointer type

Could anyone please explain me why i am seeing this warning and what need to be corrected in the above code. I am using a C99 standard compiler.

Please bear with me if my title is not very specific to what i have asked.

Answer 1

int * and int *(*)(int) are different types. You could write:

int *(*get_ptr1)(int) = (int *(*)(int))0x234456;

There is no format specifier for function pointers with printf . Your use of %x causes undefined behaviour. See this thread for some ideas.