Java流将数组收集到一个列表中

Question

I'm trying to use the new stream functionality to expand a list of strings into a longer list.

segments = segments.stream() //segments is a List<String>
    .map(x -> x.split("-"))
    .collect(Collectors.toList());

This, however, yields a List<String[]>() , which of course won't compile. How do I reduce the final stream into one list?

Answer 1

Use flatMap :

segments = segments.stream() //segments is a List<String>
    .map(x -> x.split("-"))
    .flatMap(Arrays::stream)
    .collect(Collectors.toList());

You can also remove intermediate array using Pattern.splitAsStream :

segments = segments.stream() //segments is a List<String>
    .flatMap(Pattern.compile("-")::splitAsStream)
    .collect(Collectors.toList());

Answer 2

You need to use flatMap :

segments = segments.stream() //segments is a List<String>
    .map(x -> x.split("-"))
    .flatMap(Stream::of)
    .collect(Collectors.toList());

Note that Stream.of(T... values) simply calls Arrays.stream(T[] array) , so this code is equivalent to @TagirValeev's first solution.