经典的元音练习。 我不知道为什么我的for循环无法正常工作

Question

The exercise problem- Write a function translate() that will translate a text into "rövarspråket". That is, double every consonant and place an occurrence of "o" in between. For example, translate("this is fun") should return the string "tothohisos isos fofunon".

I don't understand why my code doesn't work.

var word = prompt("Enter a word");

var vowels = ["a", "e", "i" ,"o", "u"];
var output;

for (var i=0; i < word.length; i++) {
    if (word.charAt(i) != "a" || "e" || "i" || "o" || "u" ) {
        output = word.charAt(i) + "o" + word.charAt(i);    
    } else {
        output = word.charAt(i);   
    }
    document.getElementById("paragraph").innerHTML = output;
}

Answer 1

try this:

var word = prompt("Enter a word");

var vowels = ["a", "e", "i" ,"o", "u"];
var output;

for (var i=0; i < word.length; i++) {
 if (vowels.indexOf(word.charAt(i))==-1 ) {
     output += word.charAt(i) + "o" + word.charAt(i);    
 }
    else{
     output += word.charAt(i);   
    }
    document.getElementById("paragraph").innerHTML = output;
}

Notice that i replaced the word.charAt(i) with vowels.indexOf By using indexOf you can determin if something exists in an array by the returned value.indexof returns -1 if an element doesnot exist or the index of the element inside the array

Answer 2

This code

if (word.charAt(i) != "a" || "e" || "i" || "o" || "u" ) {...}

means

If [ (word.charAt(i) !="a") or "e" or "a" ... ]

And "e" evaluates as true when cast as boolean.

The correct code to do what you're trying to do would be

if (word.charAt(i) != "a") && (word.charAt(i) != "e")  && (word.charAt(i) != "i")  && (word.charAt(i) != "o")  && (word.charAt(i) != "u") ) {...}

In addition, change both the output = commands to output+=

Answer 3

This can be achieved in one line with regex :

yourString.replace(/([bcdfghjklmnpqrstvwxz])/g, '$1o$1'); // Add the accepted characters here

In your example :

"this is fun".replace(/([bcdfghjklmnpqrstvwxz])/g, '$1o$1')

Outputs

"tothohisos isos fofunon"