在目录和子目录中找到所有文件，并提供目录的路径

Question

Hi I want to find all files in a folder including all files in the sub-folders. This is my code

all_files = []
for path, subdirs, files in os.walk(root):
    for name in files:
        all_files.append(os.path.join(path, name))
print "all_files2 = ", all_files

however the code above gives me all files with the entire path. I want all files with the path from root. So if the file is in root, I just want the the filename, if it is in the subdirectory root/images I want images/filename.. thanks carl

Answer 1

change:

all_files.append(os.path.join(path, name))

to:

all_files.append(os.path.join(path[len(root):], name))

to slice the current path starting at how long root is. ie:

>>> root = 'hello'
>>> sub = 'hello is is ew'
>>> sub[:len(root)]
'hello'
>>> sub[len(root):]
' is is ew'

you can also use relpath()

>>> os.path.relpath('root/image/thistoo','root')
'image\\thistoo'

so:

all_files.append(os.path.join(os.path.relpath(path,root), name))