php，mysql％在LIKE查询中搜索

Question

I want to find string that have % character

For example, when one row's column has %%%%%,

SELECT * FROM table WHERE column LIKE '%value%';

If value is %, it returns all.

How can I search only that row?

Answer 1

您应该使用反斜杠将其转义...

\%

Answer 2

或者，您可以将任何转义符用于：

LIKE '%|%%' escape '|'

Answer 3

You can use something like this to escape all % characters in PHP:

$original_value = "%%%%%";

$temp = str_split($original_value, 1);

$escape_value = '\\'.implode('\\', $temp);

echo $escape_value;

Result (escaped value):

\%\%\%\%\%

Answer 4

Let's say you want to find any fields that contain the text “100%”, so you put together this query:

Square Bracket Escape:

You can surround the % or _ with square brackets to tell SQL Server that the character inside is a regular character.

SELECT * FROM tablename WHERE fieldname LIKE ‘%100[%]%’

T-SQL ESCAPE Syntax:

Alternatively, you can append the ESCAPE operator onto your query, and add a \\ character before the value you want to escape.

SELECT * FROM tablename WHERE fieldname LIKE ‘%100\%%’ ESCAPE ‘\’

The ESCAPE '\\' part of the query tells the SQL engine to interpret the character after the \\ as a literal character instead of as a wildcard.

The easiest way is to include the characters I don't want, for example square brackets and slash:

SELECT * FROM Table
WHERE Name LIKE '%[\]\[/]%' ESCAPE '\'