PHP URL解析和编辑

Question

I searched "the whole" stackoverflow but didn't find a decent answer that works for me. I need to change the host of a url in php.

This url: http://example123.com/query?t=de&p=9372&pl=bb02799a&cat=&sz=400x320&scdid=e7311763324c781cff2d3bc55b2d83327aba111f2db79d0682860162c8a13c24&rnd=29137126

To This: http://example456.com/test?t=de&p=9372&pl=bb02799a&cat=&sz=400x320&scdid=e7311763324c781cff2d3bc55b2d83327aba111f2db79d0682860162c8a13c24&rnd=29137126

I only need to change the domain and the path or file, so far I've got this:

$originalurl = http://example123.com/query?t=de&p=9372&pl=bb02799a&cat=&sz=400....
$parts = parse_url($originalurl);
$parts['host'] = $_SERVER['HTTP_HOST'];
$parts['path'] = '/test';
$modifiedurl = http_build_query($parts);
print_r(urldecode($modifiedurl));

but it echos

scheme=http&host=localhost&path=/test&query=t=de&p=9372&pl=bb02799a&cat=&sz=400...

Please I don't want to use some strpos or something like that as I need it to be variable. Thanks ;)

Answer 1

You'll have to do some concatenating manually. This works:

$originalurl = "http://example123.com/query?t=de&p=9372";
$parts = parse_url($originalurl);
$new_path = '/test';
$modifiedurl = $parts['scheme'] . "://" . $_SERVER['HTTP_HOST'] . $new_path . (isset($parts['query']) ? "?".$parts['query']:"");
print_r($modifiedurl);

Answer 2

$url = 'http://example123.com/query?t=de&p=9372&pl=bb02799a&cat=&sz=400x320&scdid=e7311763324c781cff2d3bc55b2d83327aba111f2db79d0682860162c8a13c24&rnd=29137126';
$query = parse_url($url)['query'];

$newUrl = 'http://www.younewdomain.com/path?' . $query;

Answer 3

Came up with a different approach:

$url = "http://example123.com/query?t=de&p=9372&pl=bb02799a&cat=&sz=400x320&scdid=e7311763324c781cff2d3bc55b2d83327aba111f2db79d0682860162c8a13c24&rnd=29137126";
$new_host = "http://newhost.com/blab";

//explode at ? so you get the query
$split = explode("?",$url,2);

//build new url
$new_url = $new_host."?".$split[1];

//finish
echo $new_url;

Answer 4

parse_url（）的反向函数应该是http_build_url（） ，您是否尝试过？