[英]How do I turn PHP string into slug in Wordpress
I have a page in wordpress I am using with a slug called Bad-Debt-Recovery-in/
. 我在wordpress中有一个页面,正在使用一个名为Bad-Debt-Recovery-in/
。 I am using a custom php query on that page with strings in the URL's like this 我正在该页面上使用自定义php查询,URL中的字符串是这样的
Bad-Debt-Recovery-in/?zipcode=55555&location=Chambers%20County+AL
How can I make this url into a slug like this 我怎样才能使这个URL变成这样的
Bad-Debt-Recovery-in/55555/Chambers-County/AL/
as a rewrite? 作为重写? Any help would be appreciated! 任何帮助,将不胜感激!
UPDATE: This code is actually what I am using. 更新:这段代码实际上是我正在使用的。 I also made it simpler and created a third variable named "state". 我还简化了操作,并创建了第三个名为“ state”的变量。 One rewrite is for City and one is for County page: 一种是针对城市的重写,另一种是针对县的重写:
# BEGIN WordPress
<IfModule mod_rewrite.c>
RewriteEngine On
RewriteBase /
RewriteRule ^Bad-Debt-Recovery-And-Collection-Agencies-Services-In\/([^\/]+)\/([^\/]+)\/([^\/]+)\/? Bad-Debt-Recovery-And-Collection-Agencies-Services-In/?zipcode=$1&city=$2&state=$3 [QSA,L,NC]
RewriteRule ^Bad-Debt-Recovery-And-Collection-Agency-Services-In\/([^\/]+)\/([^\/]+)\/([^\/]+)\/? Bad-Debt-Recovery-And-Collection-Agency-Services-In/?countyid=$1&county=$2&state=$3 [QSA,L,NC]
RewriteRule ^index\.php$ - [L]
RewriteCond %{REQUEST_FILENAME} !-f
RewriteCond %{REQUEST_FILENAME} !-d
RewriteRule . /index.php
</IfModule>
# END WordPress
You can use the WP function sanitize_title
您可以使用WP 函数sanitize_title
Combine this with a php loop ie 结合这个与PHP循环即
$url = $_SERVER['REQUEST_URI'];
foreach($_GET as $g){
$url .= '/'.$g;
}
$url = sanitize_title($url);
What you are asking for, and seeking to accomplish is called: Converting a request path into a query string. 您要求和寻求完成的工作称为:将请求路径转换为查询字符串。
Use .htaccess RewriteRule directive to modify the incoming request 使用.htaccess RewriteRule指令修改传入请求
RewriteRule ^Bad-Debt-Recovery-in\/([^\/]+)\/([^\/]+)\/([^\/]+)\/? Bad-Debt-Recovery-in/?a=$1&b=$2&c=$3 [QSA,L,NC]
Each ([^\\/]+)
captures path elements into a variables $1,$2,$3...
每个([^\\/]+)
将路径元素捕获到变量$1,$2,$3...
The ?
?
at the end simply denotes that the last /
is optional or else the last match could fail 最后仅表示last /
是可选的,否则最后的匹配可能失败
the \\
simply escape the '/' for literal interpretation \\
只是将'/'转义为文字解释
Add as many ([^\\/]+)
as needed and capture them in the query 根据需要添加尽可能多的([^\\/]+)
并将其捕获到查询中
zipcode=$1&location=$2+$3
The modifiers at the end [QSA,L,NC]
are called flags [QSA,L,NC]
结尾的修饰符称为标志
This is your final solution: 这是您的最终解决方案:
RewriteRule ^Bad-Debt-Recovery-in\/([^\/]+)\/([^\/]+)\/([^\/]+)\/? Bad-Debt-Recovery-in/?zipcode=$1&location=$2+$3 [QSA,L,NC]
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