为每个列表项调用不同的函数

Question

Let's say I have a list like this:

[1, 2, 3, 4]

And a list of functions like this:

[a, b, c, d]

Is there an easy way to get this output? Something like zip , but with functions and arguments?

[a(1), b(2), c(3), d(4)]

Answer 1

Use zip() and a list comprehension to apply each function to their paired argument:

arguments = [1, 2, 3, 4]
functions = [a, b, c, d]

results = [func(arg) for func, arg in zip(functions, arguments)]

Demo:

>>> def a(i): return 'function a: {}'.format(i)
...
>>> def b(i): return 'function b: {}'.format(i)
...
>>> def c(i): return 'function c: {}'.format(i)
...
>>> def d(i): return 'function d: {}'.format(i)
...
>>> arguments = [1, 2, 3, 4]
>>> functions = [a, b, c, d]
>>> [func(arg) for func, arg in zip(functions, arguments)]
['function a: 1', 'function b: 2', 'function c: 3', 'function d: 4']

Answer 2

arguments = [1, 2, 3, 4]
functions = [a, b, c, d]

def process(func, arg):
    return func(arg)

results = map(process, functions, arguments)

define a function process to do the job, and use map to iterate the functions with its arguments