[英]LinkedList returning method
Is it possible to create a method returning a LinkedList and what would be the correct syntax ? 是否可以创建一个返回LinkedList的方法,正确的语法是什么?
public LinkedList static void NewtonRaphson1() {
return linkedlist;
}
swap the static
and the return type
and remove the void
: 交换static
和return type
并删除void
:
public static LinkedList<String> NewtonRaphson1() {
return new LinkedList<String>();
}
you have defined a wrong syntax. 您定义了错误的语法。
Edit: As Tunaki mentioned it is better to use generic and declare the type of data that is in your list: 编辑:正如Tunaki提到的,最好使用泛型并声明列表中的数据类型:
LinkedList<String>
LinkedList<Integer>
LinkedList<Float>
LinkedList<MyObjectClass>
otherwise you get a warning from your IDE 否则,您会从IDE中收到警告
"LinkedList is a raw type. References to generic type LinkedList should be parameterized" “ LinkedList是原始类型。对泛型类型LinkedList的引用应参数化”
the great benefit of that is: 这样做的最大好处是:
- Stronger type check during compile time 编译期间进行更严格的类型检查
- you dont need casting. 你不需要铸造。
omit the "void", a void method return nothing ... 省略“ void”,void方法不返回任何内容...
public static LinkedList NewtonRaphson1() {
return linkedlist;
}
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