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MySQL旋转行和列

[英]MySQL Pivoting rows and columns

I have a table with some user data, and a second one with user properties data. 我有一个包含一些用户数据的表,还有一个包含用户属性数据的表。 The properties are always going to be 2, and I know their name. 属性始终为2,我知道它们的名称。 I need a query to retrieve everything in a single structure. 我需要一个查询来检索单个结构中的所有内容。 I cannot alter, however, the database schema. 但是,我无法更改数据库架构。

This is the simplified version of my database: 这是数据库的简化版本:

USER 用户

+-------------------+--------------+------+-----+---------+-------+
| Field             | Type         | Null | Key | Default | Extra |
+-------------------+--------------+------+-----+---------+-------+
| username          | varchar(64)  | NO   | PRI | NULL    |       |
| name              | varchar(100) | YES  |     | NULL    |       |
+-------------------+--------------+------+-----+---------+-------+

USER_PROPERTIES USER_PROPERTIES

+-----------+--------------+------+-----+---------+-------+
| Field     | Type         | Null | Key | Default | Extra |
+-----------+--------------+------+-----+---------+-------+
| username  | varchar(64)  | NO   | PRI | NULL    |       |
| propName  | varchar(100) | NO   | PRI | NULL    |       |
| propValue | text         | NO   |     | NULL    |       |
+-----------+--------------+------+-----+---------+-------+

So, having for example, this data: 因此,例如,具有以下数据:

USER 用户

username         name
1                User1
2                User2

USER_PROPERTIES USER_PROPERTIES

username         propName         propValue
1                status           "At work"
1                picture          "pict1.jpg"
2                status           "Busy"
2                picture          "pict2.jpg"

I would need the following result: 我需要以下结果:

username         name             STATUS          PICTURE
1                User1            "At work"       "pict1.jpg"
2                User2            "Busy"          "pict2.jpg"

I did some research in Internet and apparently this is achieved with PIVOT, but MySQL does not contain this functionality. 我在Internet上做了一些研究,显然这是通过PIVOT实现的,但是MySQL不包含此功能。 By following the answers here: MySQL pivot table , I could manage to get this: 通过遵循以下答案: MySQL数据透视表 ,我可以设法做到这一点:

select ou.username, 
    case when (oup.propName='status') then oup.propValue end as 'STATUS',
    case when (oup.propName='picture') then oup.propValue end as 'PICTURE'
from User ou, User_Properties oup
where ou.username = oup.username;

username         name             STATUS          PICTURE
1                User1            "At work"       null
1                User1            null            "pict1.jpg"
2                User2            "Busy"          null
2                User2            null            "pict2.jpg"

The results are in two different lines. 结果在两个不同的行中。 If I group the results by username, I get the PICTURE data always as null: 如果按用户名对结果进行分组,则将PICTURE数据始终为null:

select ou.username, 
    case when (oup.propName='status') then oup.propValue end as 'STATUS',
    case when (oup.propName='picture') then oup.propValue end as 'PICTURE'
from User ou, User_Properties oup
where ou.username = oup.username
group by oup.username;

username         name             STATUS          PICTURE
1                User1            "At work"       null
2                User2            "Busy"          null

What am I missing? 我想念什么? Thanks. 谢谢。

EDIT: https://stackoverflow.com/users/1529673/strawberry gave the solution: 编辑: https : //stackoverflow.com/users/1529673/strawberry提供了解决方案:

select ou.username, 
    MAX(case when (oup.propName='status') then oup.propValue end) as 'STATUS',
    MAX(case when (oup.propName='picture') then oup.propValue end) as 'PICTURE'
from User ou, User_Properties oup
where ou.username = oup.username;

https://stackoverflow.com/users/1529673/strawberry gave the solution: https://stackoverflow.com/users/1529673/strawberry提供了解决方案:

select ou.username, 
    MAX(case when oup.propName='status' then oup.propValue end) as 'STATUS',
    MAX(case when oup.propName='picture' then oup.propValue end) as 'PICTURE'
from User ou
Join User_Properties oup
On ou.username = oup.username;

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