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选择多个最大值

[英]selecting multiple max values

i have a table like this on a mysql database: 我在mysql数据库上有这样的表:

id | item
-----------
1  | 2
2  | 2
3  | 4
4  | 5
5  | 8
6  | 8
7  | 8

i want the result to be 3 record with the highest Item value 我希望结果是具有最高Item值的3条记录

select max(item) returns only 1 value how can i select multiple max values? select max(item)仅返回1个值如何选择多个最大值? thank you 谢谢

You can use a derived table to get the maximum value and join it back to the original table to see all rows corresponding to it. 您可以使用派生表获取最大值,然后join其联接回原始表以查看与其对应的所有行。

select t.id, t.item 
from tablename t
join (select max(item) as mxitem from tablename) x
on x.mxitem = t.item

Edit: 编辑:

select t.co_travelers_id, t.booking_id, t.accounts_id 
from a_co_travelers t
join (select accounts_id, max(booking_id) as mxitem 
      from a_co_travelers
      group by accounts_id) x 
on x.mxitem = t.booking_id and t.accounts_id = x.accounts_id

If you use an 'aggregate function' without GROUP BY only one row will be returned. 如果您使用不带GROUP BY的“聚合函数”,则仅返回一行。

You may use GROUP BY , with aggregate functions. 您可以将GROUP BY与聚合函数一起使用。

Here is SQLFiddle Demo 这是SQLFiddle演示

SELECT id,max(item) AS item 
 FROM table_name
 GROUP BY id 
 ORDER BY item DESC 
 LIMIT 3

Hope this helps. 希望这可以帮助。

There is the graphical explanation . 有图形说明 There is script mysql (low abstraction level, no inner join or sth) 有脚本mysql(低抽象级别,没有内部联接或某物)

select * from ocena, uczen where ocena.ocena = (SELECT MAX(ocena.ocena) FROM ocena WHERE ocena.przedmiot_id="4" and ocena.uczen_id="1") and ocena.uczen_id=uczen.id and ocena.przedmiot_id="4" and uczen_id="1" 

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