要求用户输入浮点值。 如果无效输入超过两次，请使用python退出程序

Question

I have to make a function that requests non-zero floating-point values from the user; when the user enters 0, the sum of the numbers input is printed. The function terminates when the user enters two invalid inputs in a row.

I have the following code:

def inValues():
    counter = 0
    s = 0

    while True:
        if counter <= 2:
            try:
                digit = input('Please enter a number: ')
                counter += 1
                floatDig = float(digit)
                break
        else:
            break
        except:
            print('Error. Please re-enter the value.')
    if floatDig == 0:
        s += sum(floatDig)
        return s

But when ran, it asks for one input only, then stops. I'm pretty sure the code is pretty scrambled and broken so any help is appreciated.

Answer 1

Few notes:

• A while loop can have a condition - so I use it for the error counting
• The break exits the while loop - so I removed it (we now use it for monitoring error count).
• I immediately check if the user wants to quit
• The error counter is only increased on error.

Code:

def inValues():
    errorcounter = 0
    s = 0

    while errorcounter < 2: # errorcounter = [0, 1] ...
        digit = input('Please enter a number: ')
        if digit == '0':
            # return sum of numbers
            return s
        try:
            # try and summarize input
            s += float(digit)
        except:
            print('Error. Please re-enter the value.')
            errorcounter += 1

    print("Too many errors.")
    # possibly return indicative value (None?)