[英]Binary Tree only adding to the the root
I'm writing a simple Binary Tree program in C++ and right now it only stores the most recent value entered at the root node eg. 我正在用C ++写一个简单的Binary Tree程序,现在它只存储在根节点上输入的最新值,例如。 if I enter 10 into the tree then 9 into the tree, 9 just overwrites 10 as the root node so the tree only stores the value 9.
如果我在树中输入10,然后在树中输入9,则9会覆盖10作为根节点,因此树仅存储值9。
I've looked at multiple C++ Binary Tree solutions online and tried their version of implementing them yet I still get no success. 我在线上查看了多个C ++ Binary Tree解决方案,并尝试了其实现它们的版本,但仍然没有成功。
Here is my struct for a single node in the tree 这是我对树中单个节点的结构
struct TreeNode{
int value;
TreeNode *left;
TreeNode *right;
TreeNode(int value){
this -> value = value;
left = NULL;
right = NULL;
}
};
My class for the binary tree so far 到目前为止我的二叉树课程
class IntTree{
private :
TreeNode *root;
public :
IntTree();
TreeNode* getRoot();
void insertValue(TreeNode *root, int intValue);
TreeNode* searchTree(TreeNode *root, int intValue);
void inOrder(TreeNode *root);
void deleteValue(int intValue);
void deleteTree(TreeNode *root);
};
The Insert Method 插入方法
void IntTree::insertValue(TreeNode *root, int intValue){
if(root == NULL){
root = new TreeNode(intValue);
}
else if(intValue == root->value){
cout << "Value already exists in the tree" << endl;
}
else if(intValue < root->value){
insertValue(root->left, intValue);
}
else{
insertValue(root->right, intValue);
}
}
And then this method is simply called in a menu like this 然后在这样的菜单中简单地调用此方法
cout << "Enter Value to Insert : " << endl;
input = readInt();
theTree.insertValue(theTree.getRoot(), input);
The logic all seems fine to me, apart from that I've tried not using a constructor and just induvidually setting the variable, having two functions for inserting one with just the int parameter which so I don't have to use the getRoot() later on and a million other things which I've forgotten 逻辑对我来说似乎还不错,除了我尝试不使用构造函数,而只是通过工业设置变量,有两个函数可以仅使用int参数插入一个函数,因此我不必使用getRoot()后来还有我忘记的一百万件事
The answer is simple, the pointer you are modifying is only a copy, so the copy is discarded at the end of the function and you have lost memory. 答案很简单,您正在修改的指针只是一个副本,因此该副本在函数末尾被丢弃,并且您已经失去了内存。 You need to take a reference on the pointer to actually modify it (nothing else to modify):
您需要在指针上进行引用以实际对其进行修改(无需修改):
void insertValue(TreeNode *& root, int intValue)
This should work: 这应该工作:
New insertvalue function call will look as below 新的insertvalue函数调用将如下所示
void insertValue(TreeNode **root, int intValue)
{
if(*root == NULL)
{
*root = newNode(intValue);
}
else if(intValue == (*root)->value)
{
cout << "Value already exists in the tree" << endl;
}
else if(intValue < (*root)->value)
{
insertValue(&(*(root))->left, intValue);
}
else
{
insertValue(&(*(root))->right, intValue);
}
}
int main()
{
//initial code
insertvalue(&root,value) //root is a single pointer variable.
//code for printing the tree
}
There are many less complex ways to implement the same. 有许多不太复杂的方法可以实现相同的目的。 i have just modified your code.
我刚刚修改了您的代码。
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